仅显示一对多选择的最佳结果

时间:2011-07-22 19:37:57

标签: mysql sql select one-to-many

我无法理解如何处理我在SQL中想到的事情。我有书签,以及用户发布的关于它们的评论。我正在使用单个表格来表达所有评论。因此,我们在书签和评论之间存在一对多的关系。

还有另一张表,作为中间人,将每个书签与其所有评论联系起来。

有两种类型的评论。建议的书签标题和一般注释。建议的标题既有标题也有描述,而一般评论只有描述。还有一个建议标题的评级系统,因此主页可以为每个要显示的书签选择最高评分的标题。

所以,主要的事情要弄清楚。 Bookmarks表有BID和URL,还有带有CID,Title,Comment和Rating的Comments表。 BooksNComms是它们之间的连接表。

    SELECT comments.title, comments.comment
      FROM comments
INNER JOIN booksncomms ON comments.cid=booksncomms.cid
     WHERE booksncomms.bid=1
       AND comments.title is not null
  ORDER BY comments.rating
     LIMIT 0, 1;

以上方法可以获得某个BID的最佳标题和描述(评论)。我想要做的就是为10个最新的书签做上述工作。

    SELECT bookmarks.url, comments.title, comments.`comment`, comments.rating
      FROM bookmarks
INNER JOIN booksncomms 
        ON bookmarks.bid=booksncomms.bid
INNER JOIN comments 
        ON comments.cid=booksncomms.cid
      JOIN (
            SELECT bookmarks.bid 
              FROM bookmarks 
          ORDER BY bookmarks.datecreated DESC 
             LIMIT 1
        )
        AS a 
        ON a.bid=bookmarks.bid
     WHERE comments.title IS NOT NULL
  ORDER BY bookmarks.url;

上面给出了10个最新书签的所有标题。

有没有办法可以为10个最新的书签中的每一个选择最高评分?

2 个答案:

答案 0 :(得分:1)

(OP自己的解决方案,与问题分开)

@LefterisAslanoglou说:

  

我在这里发布问题后几分钟才意识到我知道了答案。它已经困扰了我好几个小时,但这是一个简单的问题,即为每个书签获得一个具有最佳评级标题的表格,然后加入具有最新书签的所有标题的表格。

    SELECT bookmarks.url, comments.title, comments.comment, comments.rating
      FROM bookmarks
INNER JOIN booksncomms ON bookmarks.bid=booksncomms.bid
INNER JOIN comments ON comments.cid=booksncomms.cid
      JOIN (
           SELECT bookmarks.bid 
             FROM bookmarks 
         ORDER BY bookmarks.datecreated DESC 
            LIMIT 10
      ) AS a ON a.bid=bookmarks.bid
      JOIN (
          SELECT comments.cid, MAX(comments.rating) 
              AS maxrating
            FROM comments
      INNER JOIN booksncomms ON comments.cid=booksncomms.cid
        GROUP BY booksncomms.bid
      ) AS b ON b.cid=comments.cid
     WHERE comments.title IS NOT NULL
  ORDER BY bookmarks.datecreated DESC;

答案 1 :(得分:0)

尝试

    SELECT bookmarks.url, comments.title, comments.`comment`, MAX(comments.rating) rating
      FROM bookmarks
INNER JOIN booksncomms 
        ON bookmarks.bid = booksncomms.bid
INNER JOIN comments 
        ON comments.cid = booksncomms.cid
     WHERE comments.title IS NOT NULL
  ORDER BY bookmarks.datecreated DESC, bookmarks.url
     LIMIT 10
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