我有一个大数据集,根据产品生命周期(以年为单位)的平均值,我从中创建了 4 个组。我想比较我第一次执行 Levene 检验以验证方差的同质性并发现显着差异的均值和方差。现在,由于对方差分析的假设不成立,我不确定是否可以使用“userfriendlyscience”中的函数 oneway() 执行 Games-Howell 测试,该函数也为方差分析提供了拟合(请参见下面的结果)。我现在有两件事需要帮助:
Omega squared: 95% CI = [.01; .01], point estimate = .01
Eta Squared: 95% CI = [.01; .01], point estimate = .01
SS Df MS F p
Between groups (error + effect) 8133.87 3 2711.29 56.65 <.001
Within groups (error only) 765609.14 15996 47.86
### Post hoc test: games-howell
diff ci.lo ci.hi t df p
Low-High -1.86 -2.30 -1.43 10.94 5048.87 <.001
Medium-High-High -1.24 -1.73 -0.76 6.60 6656.63 <.001
Medium-Low-High -1.59 -2.07 -1.11 8.54 6505.88 <.001
Medium-High-Low 0.62 0.33 0.92 5.43 6499.88 <.001
Medium-Low-Low 0.27 -0.01 0.56 2.46 6650.52 .067
Medium-Low-Medium-High -0.35 -0.70 0.00 2.54 7986.33 .053