Question

在我的 elasticsearch (7.13) 索引中，我有以下数据集：

maid      site_id    date         hour
m1        1300       2021-06-03   1
m1        1300       2021-06-03   2
m1        1300       2021-06-03   1
m2        1300       2021-06-03   1

我正在尝试从上表中获取每个日期和站点 ID 的唯一记录数。想要的结果是

maid      site_id   date        count        
m1        1300      2021-06-03  1
m2        1300      2021-06-03  1

对于每个 site_id，我有数百万的女仆，日期跨越两年。我在 maid 上使用带有 cardinality 的以下代码，假设它将返回唯一的 maid's。

GET /r_2332/_search
{
  "size":0,
  "aggs": {
    "site_id": {
      "terms": {
        "field": "site_id",
        "size":100,
        "include": [
          1171, 1048
        ]
      },"aggs" : {
          "bydate" : {
            "range" : {
              "field": "date","ranges" : [
                {
                  "from": "2021-04-08",
                  "to": "2021-04-22" 
                }
                ]
            },"aggs" : {
              "rdate" : {
                "terms" : {
                  "field":"date" 
                },"aggs" :{
                  "maids" : {
                    "cardinality": {
                      "field": "maid"
                    }
                  }
              } 
            } 
          } 
        }
      }
    }
  }
}

这仍然返回具有所有重复值的数据。我如何将 maid 字段包含在我的查询中，我可以在其中获取根据唯一 maid 值过滤的数据。

Answer 1

如果您想获得基于 site_id 和 maid 的唯一文档，您可以将 multi terms aggregation 与 cardinality aggregation 一起使用

    {
  "size": 0,
  "query": {
    "bool": {
      "filter": [
        {
          "terms": {
            "site_id": [
              "1300",
              "1301"
            ]
          }
        },
        {
          "range": {
            "date": {
              "gte": "2021-06-02",
              "lte": "2021-06-03"
            }
          }
        }
      ]
    }
  },
  "aggs": {
    "group_by": {
      "multi_terms": {
        "terms": [
          {
            "field": "site_id"
          },
          {
            "field": "maid.keyword"
          }
        ]
      },
      "aggs": {
        "type_count": {
          "cardinality": {
            "field": "site_id"
          }
        }
      }
    }
  }
}

搜索结果将是

"aggregations": {
    "group_by": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": [
            1300,
            "m1"
          ],
          "key_as_string": "1300|m1",
          "doc_count": 3,
          "type_count": {
            "value": 1           // note this
          }
        },
        {
          "key": [
            1300,
            "m2"
          ],
          "key_as_string": "1300|m2",
          "doc_count": 1,
          "type_count": {
            "value": 1            // note this
          }
        }
      ]
    }

Elasticsearch - 根据字段

1 个答案: