以编程方式调用active_record生成器：​​如何传递父参数？

Question

在所有这些情况下，忽略父参数：

Rails::Generators.invoke("active_record:model", [name, ["list_order:string", "name:string"], ["parent=Ecm::Toplist::Base"]])
Rails::Generators.invoke("active_record:model", [name, ["list_order:string", "name:string"], ["--parent=Ecm::Toplist::Base"]])
Rails::Generators.invoke("active_record:model", [name, ["list_order:string", "name:string"], "parent=Ecm::Toplist::Base"])
Rails::Generators.invoke("active_record:model", [name, ["list_order:string", "name:string"], "--parent=Ecm::Toplist::Base"])

这是一个错误，还是我错过了什么？

Answer 1

正确的方式将是

Rails::Generators.invoke("active_record:model", [name, "list_order:string", "name:string"], { parent: "Ecm::Toplist::Base"})

但是请注意，根据this，一旦指定：parent，就不会调用迁移。

使用迁移生成模型的正确方法是

Rails::Generators.invoke("active_record:model", [name, "list_order:string", "name:string"], {migration: true, timestamps: true})