检测使用UIButton阵列按下哪个按钮

时间:2011-07-22 14:25:10

标签: ios uibutton iboutlet

我有一个像这样的UIButton数组:

@property (nonatomic, retain) IBOutletCollection(UIButton) NSArray *btn_Impact_Collection;

我有这个功能:

- (IBAction)impactAction:(id)sender;

在XIB文件中,我有九个按钮,每个按钮都通过引用插座集连接到btn_Impact_Collection数组。此外,每个按钮的Touch_inside属性都连接到函数ImpactAction。

现在,当单击一个按钮时,会调用ImpactAction函数,但在此函数中,我如何知道按下了哪个按钮?

提前感谢您的回答!

4 个答案:

答案 0 :(得分:15)

将发件人转换为UIButton类,这将为您提供单击按钮的实例。我没有Xcode,但有类似的东西:

if ([sender isMemberOfClass:[UIButton class]])
{
    UIButton *btn = (UIButton *)sender;

    // Then you can reference the title or a tag of the clicked button to do some further conditional logic if you want.
    if([btn.currentTitle isEqualToString:@"title of button"])
    {
        // do something.
    }
    else if(etc...)
}

答案 1 :(得分:13)

在界面构建器(1-9)中为每个按钮设置标签,然后说

if ([sender tag] == 1) {
//First button was pressed, react.
}
else if ([sender tag] == 2) {
//Second button was pressed, react.
}
// Etc...
else {
//Last button was pressed, react.
}

对所有其他人来说也一样,或者你可以把它放在一个开关里。

答案 2 :(得分:3)

不是对标题进行字符串检查(这很慢且可能很乏味),你可以:

- (void)buttonPressed:(id)sender
{
    for( UIButton *button in self.buttonCollection )
    {
        if( sender == button )
        {
            // sender is your button (eg. you can access its tag)
        }
    }
}

答案 3 :(得分:0)

另一个选项..转发发件人以检查它是否是UIButton,然后切换sender.tag:

if ([sender isMemberOfClass:[UIButton class]]) {
        switch ([sender tag]) {
            case 0:
                //do stuff for button with tag 0
                break;

            case 1:
                //do stuff for button with tag 1
                break;

            case 2:
                ....
                break;

            default:
                break;
        }
    }