我有以下变量:
data = [(['a', 'b', '3'], ['c', 'a', 'r']),
(['*', '[', 'e'], ['33', 'gh', 'ew']),
(['23^', 're#', '4$'], ['tr', 'fF', '5%'])]
我想将 data
写入 CSV 文件,如下所示:
a c
b a
3 r
* 33
[ gh
e ew
23^ tr
re# fF
4$ 5%
请注意,在每次迭代后,中间都有一个黑色空间。
我试过了:
import csv
with open ('train.csv', 'w') as out:
writer = csv.writer(out)
for row in dataset:
writer.writerows(row)
但不能正常工作。
答案 0 :(得分:1)
由于此格式不符合 CSV 规则,因此您可以仅使用常规字符串格式来编写行。一个技巧是处理空行分隔符。假设您不希望输出文件底部有一个额外的空行,您可以获得一点创意。每组写入前先写分隔符,但以空字符串开头,第一次写入后切换到真正的分隔符。
data = [(['a', 'b', '3'], ['c', 'a', 'r']),
(['*', '[', 'e'], ['33', 'gh', 'ew']),
(['23^', 're#', '4$'], ['tr', 'fF', '5%'])]
with open("test.txt", "w") as file:
group_sep = "" # group separator written first to avoid extra blank
# line at end of file.
for group1, group2 in data:
file.write(group_sep)
group_sep = "\n"
for cell1, cell2 in zip(group1, group2):
file.write(f"{cell1} {cell2}\n")
答案 1 :(得分:0)
这应该可以完成。
data = [(['a', 'b', '3'], ['c', 'a', 'r']),
(['*', '[', 'e'], ['33', 'gh', 'ew']),
(['23^', 're#', '4$'], ['tr', 'fF', '5%'])]
with open('train.txt','w') as f:
for x in [tuple(zip(x[0],x[1])) for x in data]:
for r in x:
f.write(' '.join(r) + '\n')
f.write('\n')