Question

您好我正在关注官方文档并为我的网站设置分页，我的索引模板看起来像这样;

{% for post in list_of_posts %}
<div class="body"><a class="title" href="/post/{{post.id}}"><h2>{{ post.title }}</h2></a>
<P>{{ post.body|truncatewords:50|wordwrap:110 }}</P>    
<h3>{{ post.date|date:"jS F Y" }}</h3>
<hr>
</div>
{% endfor %}
<div class="pagination">
<span class="step-links">
    {% if post.has_previous %}
        <a href="?page={{ post.previous_page_number }}">previous</a>
    {% endif %}

    <span class="current">
            Page {{ post.number }} of {{ contacts.paginator.num_pages }}.
        </span>

        {% if post.has_next %}
        <a href="?page={{ post.next_page_number }}">next</a>
        {% endif %}
    </span>
</div>

我的观点看起来像这样;

# Main page
def index(request):
list_of_posts = Post.objects.all().order_by('-date')
list_of_posts = list_of_posts.filter(published=True)
paginator = Paginator(list_of_posts, 10)
page = request.GET.get('page')
try:
    post = paginator.page(page)
except PageNotAnInteger:
    # If page is not an integer, deliver first page.
    post = paginator.page(1)
except EmptyPage:
    # If page is out of range (e.g. 9999), deliver last page of results.
    post = paginator.page(paginator.num_pages)

return render_to_response('index.html', {'list_of_posts': list_of_posts})

我觉得TypeError是因为paginator没有输出任何值？我的回溯不是很有帮助，但这里是

Exception Value:    
int() argument must be a string or a number, not 'NoneType'
Exception Location: C:\Python27\lib\site-packages\django\core\paginator.py in        validate_number, line 23
TypeError at /
int() argument must be a string or a number, not 'NoneType'

非常感谢任何可能出现问题的指导。

Answer 1

在第一个catch中添加TypeError：

except (PageNotAnInteger, TypeError):
    # ...

但如果你得到这样的页码，你也可以避免这个错误：

page = request.GET.get("page", 1)

Answer 2

视图函数的主体没有缩进。这就是它在这个页面上的表现吗？

此外，它不应该避免错误，但看起来你没有将post变量发送到模板（而不是list_of_posts）。

最后，您是否在模块的顶部有这个...

from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger

Answer 3

我在这里为pagination添加一个小代码希望它会帮助你：

def pagination(request, list_of_posts, result_per_page):
    paginator = Paginator(list_of_posts, result_per_page)
    try: // **Most probably here your code is doing somthing wrong**.
        page = int(request.GET.get('page', '1'))
    except ValueError:
        page = 1
    try:
        posts = paginator.page(page)
    except (EmptyPage, InvalidPage):
        posts = paginator.page(paginator.num_pages)

    return posts

在Django中设置分页时的Python类型错误

3 个答案: