Question

我试图找出如何从这张表中提取数据：

表：状态

OrderNo   Status   Date        User
1          1       2011-07-01  user1
1          2       2011-07-05  user1
2          1       2011-07-01  user1
2          2       2011-07-06  user2
2          3       2011-07-10  user1

我需要产生以下结果：

OrderNo   Status   Date        User
1          2       2011-07-05  user1
2          3       2011-07-10  user1

实际上，我需要的是显示OrderNo的DISTINCT列表及其最后状态。

感谢您提供所有可能的帮助。

干杯！

Answer 1

WITH S AS
(
    SELECT OrderNo, Status, Date, User
        , ROW_NUMBER() OVER
          (
              PARTITION BY OrderNo
              ORDER BY Date DESC
          ) Ranking
    FROM Status
)
SELECT OrderNo, Status, Date, User
FROM S
WHERE Ranking = 1

Answer 2

select OrderNo, max(Status) as 'Status'
from Status
group by OrderNo

多个场产生的独特记录

2 个答案: