我想在正确处理cookie的同时向远程服务器发出http请求（例如，存储服务器发送的cookie，并在我发出后续请求时发送这些cookie）。保留任何和所有cookie都很好，但实际上我唯一关心的是会话cookie。
使用java.net，似乎首选的方法是使用java.net.CookieHandler（抽象基类）和java.net.CookieManager（具体实现）。 Android有java.net.CookieHandler，但它似乎没有java.net.CookieManager。
我可以通过检查http标头手动编写所有代码，但似乎必须有一种更简单的方法。
在保留Cookie的同时在Android上发出http请求的正确方法是什么？
答案 0 :(得分：90)
事实证明，谷歌Android附带了Apache HttpClient 4.0，我能够使用HttpClient docs中的“基于表单的登录”示例找出如何做到这一点：
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.cookie.Cookie;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;
/**
* A example that demonstrates how HttpClient APIs can be used to perform
* form-based logon.
*/
public class ClientFormLogin {
public static void main(String[] args) throws Exception {
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet("https://portal.sun.com/portal/dt");
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
System.out.println("Login form get: " + response.getStatusLine());
if (entity != null) {
entity.consumeContent();
}
System.out.println("Initial set of cookies:");
List<Cookie> cookies = httpclient.getCookieStore().getCookies();
if (cookies.isEmpty()) {
System.out.println("None");
} else {
for (int i = 0; i < cookies.size(); i++) {
System.out.println("- " + cookies.get(i).toString());
}
}
HttpPost httpost = new HttpPost("https://portal.sun.com/amserver/UI/Login?" +
"org=self_registered_users&" +
"goto=/portal/dt&" +
"gotoOnFail=/portal/dt?error=true");
List <NameValuePair> nvps = new ArrayList <NameValuePair>();
nvps.add(new BasicNameValuePair("IDToken1", "username"));
nvps.add(new BasicNameValuePair("IDToken2", "password"));
httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
response = httpclient.execute(httpost);
entity = response.getEntity();
System.out.println("Login form get: " + response.getStatusLine());
if (entity != null) {
entity.consumeContent();
}
System.out.println("Post logon cookies:");
cookies = httpclient.getCookieStore().getCookies();
if (cookies.isEmpty()) {
System.out.println("None");
} else {
for (int i = 0; i < cookies.size(); i++) {
System.out.println("- " + cookies.get(i).toString());
}
}
// When HttpClient instance is no longer needed,
// shut down the connection manager to ensure
// immediate deallocation of all system resources
httpclient.getConnectionManager().shutdown();
}
}
答案 1 :(得分：8)
Cookie只是另一个HTTP标头。您始终可以在使用apache库或HTTPUrlConnection进行HTTP调用时进行设置。无论哪种方式，您都应该能够以这种方式读取和设置HTTP cookie。
您可以阅读this article了解详情。
我可以分享我的代码和平，以证明你可以轻松实现它。
public static String getServerResponseByHttpGet(String url, String token) {
try {
HttpClient client = new DefaultHttpClient();
HttpGet get = new HttpGet(url);
get.setHeader("Cookie", "PHPSESSID=" + token + ";");
Log.d(TAG, "Try to open => " + url);
HttpResponse httpResponse = client.execute(get);
int connectionStatusCode = httpResponse.getStatusLine().getStatusCode();
Log.d(TAG, "Connection code: " + connectionStatusCode + " for request: " + url);
HttpEntity entity = httpResponse.getEntity();
String serverResponse = EntityUtils.toString(entity);
Log.d(TAG, "Server response for request " + url + " => " + serverResponse);
if(!isStatusOk(connectionStatusCode))
return null;
return serverResponse;
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
答案 2 :(得分：4)
由于 Apache库已被弃用，对于那些想要使用HttpURLConncetion的人，我写了这个类，在this answer的帮助下发送Get和Post Request：
public class WebService {
static final String COOKIES_HEADER = "Set-Cookie";
static final String COOKIE = "Cookie";
static CookieManager msCookieManager = new CookieManager();
private static int responseCode;
public static String sendPost(String requestURL, String urlParameters) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json; charset=utf-8");
if (msCookieManager.getCookieStore().getCookies().size() > 0) {
//While joining the Cookies, use ',' or ';' as needed. Most of the server are using ';'
conn.setRequestProperty(COOKIE ,
TextUtils.join(";", msCookieManager.getCookieStore().getCookies()));
}
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
if (urlParameters != null) {
writer.write(urlParameters);
}
writer.flush();
writer.close();
os.close();
Map<String, List<String>> headerFields = conn.getHeaderFields();
List<String> cookiesHeader = headerFields.get(COOKIES_HEADER);
if (cookiesHeader != null) {
for (String cookie : cookiesHeader) {
msCookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
}
}
setResponseCode(conn.getResponseCode());
if (getResponseCode() == HttpsURLConnection.HTTP_OK) {
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line = br.readLine()) != null) {
response += line;
}
} else {
response = "";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
// HTTP GET request
public static String sendGet(String url) throws Exception {
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
// optional default is GET
con.setRequestMethod("GET");
//add request header
con.setRequestProperty("User-Agent", "Mozilla");
/*
* https://stackoverflow.com/questions/16150089/how-to-handle-cookies-in-httpurlconnection-using-cookiemanager
* Get Cookies form cookieManager and load them to connection:
*/
if (msCookieManager.getCookieStore().getCookies().size() > 0) {
//While joining the Cookies, use ',' or ';' as needed. Most of the server are using ';'
con.setRequestProperty(COOKIE ,
TextUtils.join(";", msCookieManager.getCookieStore().getCookies()));
}
/*
* https://stackoverflow.com/questions/16150089/how-to-handle-cookies-in-httpurlconnection-using-cookiemanager
* Get Cookies form response header and load them to cookieManager:
*/
Map<String, List<String>> headerFields = con.getHeaderFields();
List<String> cookiesHeader = headerFields.get(COOKIES_HEADER);
if (cookiesHeader != null) {
for (String cookie : cookiesHeader) {
msCookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
}
}
int responseCode = con.getResponseCode();
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
return response.toString();
}
public static void setResponseCode(int responseCode) {
WebService.responseCode = responseCode;
Log.i("Milad", "responseCode" + responseCode);
}
public static int getResponseCode() {
return responseCode;
}
}
答案 3 :(得分：1)
我不使用谷歌Android，但我认为你会发现它并不难以让这个工作。如果您阅读the relevant bit of the java tutorial，您将看到已注册的cookiehandler从HTTP代码获得回调。
因此，如果没有默认值（你检查过CookieHandler.getDefault()是否确实为空？）那么你可以简单地扩展CookieHandler，实现put / get并使其自动运行。如果你走这条路，一定要考虑并发访问等。
编辑：显然，您必须通过CookieHandler.setDefault()将自定义实现的实例设置为默认处理程序才能接收回调。忘记提及。