Question

我是编程新手，并且至少在几个小时内一直在努力解决这个问题。它简单地向玩家发放5张牌。这是我的代码：

<?php
//setting up arrays
$cardLocation = array();
$suits = array("Hearts", "Diamonds", "Spades", "Clubs");
$ranks = array("Ace", 2, 3, 4, 5, 6, 7, 8, 9, 10, "Jack","Queen", "King");

//filling the deck
for($rank=0; $rank<13; $rank++){
  for($suit=0; $suit<4; $suit++){
    $cardLocation[$rank][$suit] = "deck";
  }
}

//dealing the cards to a player
for($i=0; $i<5; $i++){

$duplicate = true;

while($duplicate){
  $suit = rand(1, 4);
  $rank = rand(1, 13);
  if($cardLocation[$rank][$suit] == "deck"){
      $cardLocation[$rank][$suit] = "player";
      $duplicate = false;

    }
  }
}

?>

我正在试图找出一种方法，将for循环的每个值存储到一个数组中，然后将其打印出来。有一些想法，但所有的想法都失败了。任何帮助都会受到欢迎。

Answer 1

我不确定是否需要二维数组，但如果不是，你可以考虑这样的事情：

<?php

const NUMBER_OF_CARDS_TO_DRAW = 5;

$cardLocation = array();
$suits = array("Hearts", "Diamonds", "Spades", "Clubs");
$ranks = array("Ace", 2, 3, 4, 5, 6, 7, 8, 9, 10, "Jack","Queen", "King");

//filling the deck
$deck = [];
foreach ($suits as $suit) {
    foreach ($ranks as $rank) {
        $deck[] = "$suit $rank";
    }
}

// http://php.net/manual/en/function.shuffle.php
shuffle($deck);

$playerHand = [];

for ($i=0;$i<NUMBER_OF_CARDS_TO_DRAW;$i++) {
    // http://php.net/manual/en/function.array-shift.php
    $randomCard = array_shift($deck);
    if (is_null($randomCard)) {
        // this happens if you try to draw too many cards
        break;
    }
    $playerHand[] = $randomCard;
}

print_r($playerHand);

如何在数组中存储for循环的值？

1 个答案: