我需要转置大型数据框,因此我使用了:
df.aree <- t(df.aree)
df.aree <- as.data.frame(df.aree)
这是我获得的:
df.aree[c(1:5),c(1:5)]
10428 10760 12148 11865
name M231T3 M961T5 M960T6 M231T19
GS04.A 5.847557e+03 0.000000e+00 3.165891e+04 2.119232e+04
GS16.A 5.248690e+04 4.047780e+03 3.763850e+04 1.187454e+04
GS20.A 5.370910e+03 9.518396e+03 3.552036e+04 1.497956e+04
GS40.A 3.640794e+03 1.084391e+04 4.651735e+04 4.120606e+04
我的问题是我需要消除的新列名称(10428,10760,12148,11865),因为我需要将第一行用作列名。
我尝试使用col.names()
功能但我没有得到我需要的功能。
你有什么建议吗?
修改
感谢您的建议!使用它我获得:
df.aree[c(1:5),c(1:5)]
M231T3 M961T5 M960T6 M231T19
GS04.A 5.847557e+03 0.000000e+00 3.165891e+04 2.119232e+04
GS16.A 5.248690e+04 4.047780e+03 3.763850e+04 1.187454e+04
GS20.A 5.370910e+03 9.518396e+03 3.552036e+04 1.497956e+04
GS40.A 3.640794e+03 1.084391e+04 4.651735e+04 4.120606e+04
GS44.A 1.225938e+04 2.681887e+03 1.154924e+04 4.202394e+04
现在我需要在因子列中转换行名(GS ..)....
答案 0 :(得分:91)
当名称列在其中时,最好不要转置data.frame - 然后所有数值都将转换为字符串!
这是一个将数字保持为数字的解决方案:
# first remember the names
n <- df.aree$name
# transpose all but the first column (name)
df.aree <- as.data.frame(t(df.aree[,-1]))
colnames(df.aree) <- n
df.aree$myfactor <- factor(row.names(df.aree))
str(df.aree) # Check the column types
答案 1 :(得分:46)
df.aree <- as.data.frame(t(df.aree))
colnames(df.aree) <- df.aree[1, ]
df.aree <- df.aree[-1, ]
df.aree$myfactor <- factor(row.names(df.aree))
答案 2 :(得分:33)
您可以使用transpose
库中的data.table
功能。简单快速的解决方案,将numeric
值保持为numeric
。
library(data.table)
# get data
data("mtcars")
# transpose
t_mtcars <- transpose(mtcars)
# get row and colnames in order
colnames(t_mtcars) <- rownames(mtcars)
rownames(t_mtcars) <- colnames(mtcars)
答案 3 :(得分:1)
利用as.matrix
:
# keep the first column
names <- df.aree[,1]
# Transpose everything other than the first column
df.aree.T <- as.data.frame(as.matrix(t(df.aree[,-1])))
# Assign first column as the column names of the transposed dataframe
colnames(df.aree.T) <- names