Question

scala> implicitly[Int <:< AnyVal]
res0: <:<[Int,AnyVal] = <function1>

scala> class Foo
defined class Foo

scala> class Bar extends Foo
defined class Bar

scala> implicitly[Foo <:< Bar]
<console>:8: error: could not find implicit value for parameter e: <:<[Foo,Bar]
       implicitly[Foo <:< Bar]
                 ^

scala> implicitly[Bar <:< Foo]
res2: <:<[Bar,Foo] = <function1>

<:<约束如何工作？或者更准确地说，提供<:<的实例的隐式定义在哪里？

Answer 1

您可以在Predef中找到它。隐式方法conforms[A]提供了这些证据：

implicit def conforms[A]: A <:< A = new (A <:< A) { def apply(x: A) = x }

你可以自己尝试自己实现它，以便更清楚：

abstract class subclassOf[-From, +To] extends (From => To)
implicit def subclassOfCheck[A]: A subclassOf A = new (A subclassOf A) { def apply(x: A) = x }

implicitly[Int subclassOf AnyVal]

class Foo
class Bar extends Foo

implicitly[Bar subclassOf Foo]

Answer 2

它位于Predef对象中。

scala> implicitly[Int <:< AnyVal]
res1: <:<[Int,AnyVal] = <function1>

scala> :type res1
Predef$<:<[Int,AnyVal]

怎么＆lt;：＆lt;工作？

2 个答案: