Question

我有一个xml元素

   <base baseAtt1="aaa" baseAtt2="tt">
        <innerElement att1="one" att2="two" att3="bazinga"/>
   </base>

我希望得到属性列表。对于两者基本元素和内部元素。

我不知道 innerElement的名称它可以有许多不同的名称。

 NodeList baseElmntLst_gold  = goldAnalysis.getElementsByTagName("base");
 Element baseElmnt_gold = (Element) baseElmntLst_gold.item(0);

目标是获得一种字典作为输出，

例如对于输出上面的xml，将是一个带有这些值的字典。

baseAtt1 = "aaa"
baseAtt2 = "tt"
att1 = "one"
att2 = "two"
att3 = "bazinga"

我正在使用jre 1.5

Answer 1

这是基于纯DOM的解决方案（但是在Java中将XPath与DOM结合起来并没有错误）：

NodeList baseElmntLst_gold  = goldAnalysis.getElementsByTagName("base");
Element baseElmnt_gold = (Element) baseElmntLst_gold.item(0);

NamedNodeMap baseElmnt_gold_attr = baseElmnt_gold.getAttributes();
for (int i = 0; i < baseElmnt_gold_attr.getLength(); ++i)
{
    Node attr = baseElmnt_gold_attr.item(i);
    System.out.println(attr.getNodeName() + " = \"" + attr.getNodeValue() + "\"");
}

NodeList innerElmntLst_gold = baseElmnt_gold.getChildNodes();
Element innerElement_gold = null;
for (int i = 0; i < innerElmntLst_gold.getLength(); ++i)
{
    if (innerElmntLst_gold.item(i) instanceof Element)
    {
        innerElement_gold = (Element) innerElmntLst_gold.item(i);
        break; // just get first child
    }
}

NamedNodeMap innerElmnt_gold_attr = innerElement_gold.getAttributes();
for (int i = 0; i < innerElmnt_gold_attr.getLength(); ++i)
{
    Node attr = innerElmnt_gold_attr.item(i);
    System.out.println(attr.getNodeName() + " = \"" + attr.getNodeValue() + "\"");
}

结果：

baseAtt1 = "aaa"
baseAtt2 = "tt"
att1 = "one"
att2 = "two"
att3 = "bazinga"

Answer 2

您可以使用此XPath检索1st element节点的所有属性：

base/element[1]/@*

要获取XML中所有节点的所有属性，可以使用以下表达式：

//@*

Answer 3

如果您使用XPath，您将拥有更少的代码，但对于dom基础解决方案，我有一个建议：

public void printElementsAndAttributes() throws Exception {
    DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
    org.w3c.dom.Document doc = db.parse(new File("test.xml"));
    NodeList base = doc.getElementsByTagName("base");
    Node basenode = base.item(0);
    System.out.println(basenode.getNodeName() + getAttributesAsString(basenode.getAttributes()));
    NodeList children = basenode.getChildNodes();
    for (int i = 0; i < children.getLength(); i++) {
        Node item = children.item(i);
        if (item.getNodeType() == Node.ELEMENT_NODE) {
            System.out.println(item.getNodeName() + getAttributesAsString(item.getAttributes()));

        }
    }


}

private String getAttributesAsString(NamedNodeMap attributes) {
    StringBuilder sb = new StringBuilder("\n");
    for (int j = 0; j < attributes.getLength(); j++) {
        sb.append("\t- ").append(attributes.item(j).getNodeName()).append(": ").append(attributes.item(j).getNodeValue()).append("\n");
    }
    return sb.toString();

}

Answer 4

使用此方法..

 public static void listAllAttributes(Element element) {

             System.out.println("List attributes for node: " + element.getNodeName());

             // get a map containing the attributes of this node
                 NamedNodeMap attributes = element.getAttributes();

             // get the number of nodes in this map

             int numAttrs = attributes.getLength();


             for (int i = 0; i < numAttrs; i++) {
            Attr attr = (Attr) attributes.item(i);
            String attrName = attr.getNodeName();

 String attrValue = attr.getNodeValue();
  System.out.println("Found attribute: " + attrName + " with value: " + attrValue);

             }
 }

通过在main方法中使用以下调用来调用此方法

  NodeList entries = doc.getElementsByTagName("NameOfTheNode");
                int num = entries.getLength();
                 for (int i=0; i<num; i++) {
                                                  Element node = (Element) entries.item(i);
                                                  listAllAttributes(node);

                          }

java获取XML元素中所有属性的列表或名称

4 个答案: