我想存储以下信息:
伪代码
array(manager) = {"Prateek","Rudresh","Prashant"};
array(employee) = {"namit","amit","sushil"};
array(hr) = {"priya","seema","nakul"};
我可以使用哪种数据结构?
答案 0 :(得分:35)
您可以使用arrays来存储数据列表;和objects的键值
在你的情况下,你可能会同时使用两者:
var data = {
'manager': ["Prateek","Rudresh","Prashant"],
'employee': ["namit","amit","sushil"],
'hr': ["priya","seema","nakul"]
};
这里,data
是一个对象;其中包含三个数组。
答案 1 :(得分:13)
一个对象:
var myobj = {
"manager": ["Prateek","Rudresh","Prashant"],
"employee": ["namit","amit","sushil"],
"hr": ["priya","seema","nakul"]
}
alert(myobj['employee'][1]); // Outputs "amit"
答案 2 :(得分:10)
普通对象会:
var a = {
key1: "value1",
key2: ["value2.1","value2.2"]
/*etc*/
}
访问:
a.key1
a["key1"]
答案 3 :(得分:6)
你可以将它们存储在一个对象数组中:
var Staff = [
{ name: 'Prateek', role: manager },
{ name: 'Rudresh', role: manager },
{ name: 'Prashant', role: manager },
{ name: 'Namit', role: employee },
{ name: 'Amit', role: employee },
{ name: 'Sushil', role: employee },
{ name: 'Priya', role: hr },
{ name: 'Seema', role: hr },
{ name: 'Nakul', role: hr },
];
添加ID属性也可能有用,具体取决于您的应用程序。即
{ id: 223, name: 'Prateek', role: manager },
答案 4 :(得分:4)
使用ES2015 / ES6,您有Map类型。
使用Map你的代码看起来像
const map = new Map([
['manager', ['Prateek', 'Rudresh', 'Prashant']],
['employee', ['namit', 'amit', 'sushil']],
['hr', ['priya', 'seema', 'nakul']]
])
console.log(...map.entries())
要获得Individual值,您可以使用Map.get('key')方法
答案 5 :(得分:2)
是的,有:
var theArray = {};
theArray["manager"] = ["Prateek","Rudresh","Prashant"];
theArray["employee"] = ["namit","amit","sushil"];
theArray["hr"] = ["priya","seema","nakul"];
答案 6 :(得分:2)
或者像这样使用JSON。您的伪代码稍有变化,但它可以进行配置和扩展。
var Person = [
{
"name": "Prateek",
"position": "manager"},
{
"name": "James",
"position": "employee"}
];
答案 7 :(得分:-1)
即使您可以使用以下内容: -
var obj = new Object();
obj.name = 'Jatin';
obj.place = 'Delhi';