Question

我是node.js的新手。我正在尝试的代码中遇到一些问题。看看代码：

var http =require('http');
var url = require('url');
var events=require('events');
var e=new events.EventEmitter();

var i=0;
var clientlist=new Array();

function user(nam,channel) {
this.nam = nam;
this.chan=channel;
}

server = http.createServer(function(req,res) {
res.writeHead(200,{'Content-Type':'text/html'});
res.write('welcome');

var pathname = url.parse(req.url).pathname;
pathname=pathname.substring(1);
pathnames=pathname.split("&");
var c=new user(pathnames[0],pathnames[1]);
clientlist[i++]=c;

console.log("user "+pathnames[0]+" joined channel "+pathnames[1]);

e.emit('userjoined',clientlist[i-1].nam,clientlist[i-1].chan);

e.on('userjoined',function(n,c) {
res.write("new user joined with name: "+n+" and he joined channel "+c+"\n");
});

});
server.listen(2000);

我遇到的问题是：

我在浏览器中没有收到这行代码的欢迎消息：res.write（“welcome”）;但是，我在终端
未捕获我发出的userjoined事件。但是，在我关闭服务器之后，一切都会立刻发生。我在浏览器中收到欢迎消息，以及userjoined事件的回调。

有人能告诉我这里出了什么问题吗？感谢

Answer 1

好吧有几个问题：

您需要在调用之前声明e.on userjoined
您需要在e.on userjoined中使用res.end（）。

以下是修正的代码：

var http =require('http');
var url = require('url');
var events=require('events');
var e=new events.EventEmitter();

var i=0;
var clientlist=new Array();

function user(nam,channel) {
this.nam = nam;
this.chan=channel;
}

e.on('userjoined',function(res,n,c) {
console.log("iuser "+pathnames[0]+" joined channel "+pathnames[1]);
res.write("new user joined with name: "+n+" and he joined channel "+c+"\n");
res.end();
});

server = http.createServer(function(req,res) {
res.writeHead(200,{'Content-Type':'text/html'});
res.write('welcome');

var pathname = url.parse(req.url).pathname;
pathname=pathname.substring(1);
pathnames=pathname.split("&");

var c=new user(pathnames[0],pathnames[1]);
clientlist[i++]=c;

console.log("user "+pathnames[0]+" joined channel "+pathnames[1]);

e.emit('userjoined',res,clientlist[i-1].nam,clientlist[i-1].chan);

});
server.listen(2000);

Node.js代码问题

1 个答案: