净头寸计算

时间：2011-07-20 18:18:04

标签： mysql sql

我有一个看起来像这样的订单表：

Ticket  Open Time               Close Time              Type    Size
253199  2010-09-09 20:40:00     2010-09-09 20:41:00     sell    0.1
255406  2010-09-13 19:30:00     2010-09-14 04:30:00     buy     0.1
258089  2010-09-15 07:00:00     2010-09-15 09:15:00     sell    0.1
258197  2010-09-15 09:15:00     2010-09-15 14:50:00     buy     0.1
258203  2010-09-15 09:20:00     2010-09-15 14:50:00     buy     0.1
259659  2010-09-16 04:35:00     2010-09-16 18:35:00     sell    0.1
261065  2010-09-17 07:05:00     2010-09-20 00:02:00     buy     0.1

对于每个订单，我希望获得同时打开的所有订单（同一Type）的累计总数。换句话说，在给定订单之前打开并在给定订单之后关闭的任何订单的所有Size的总和。

这是我的代码：

DROP TABLE
IF EXISTS LongOrders;

CREATE TABLE LongOrders SELECT 
    B.Ticket AS Ticket,
    SUM(B.`Size`)AS `Cumulative Long`
FROM
    `orders`.eurusd_fx AS A
JOIN `orders`.eurusd_fx AS B ON(
    B.`Close Time` >= A.`Open Time`
    AND B.`Open Time` <= A.`Open Time`
    AND A.Type = B.Type
    AND A.Type = 'buy'
)
GROUP BY
    A.`Open Time`
ORDER BY
    A.`Open Time`;

DROP TABLE
IF EXISTS ShortOrders;

CREATE TABLE ShortOrders SELECT
    B.Ticket AS Ticket,
    SUM(B.`Size`)AS `Cumulative Short`
FROM
    `orders`.eurusd_fx AS A
JOIN `orders`.eurusd_fx AS B ON(
    B.`Close Time` >= A.`Open Time`
  AND B.`Open Time` <= A.`Open Time`
    AND A.Type = B.Type
    AND A.Type = 'sell'
)
GROUP BY
    A.`Open Time`
ORDER BY
    A.`Open Time`;

DROP TABLE
IF EXISTS CumLong;

CREATE TABLE CumLong SELECT
    A.*
FROM
    LongOrders AS A
JOIN `orders`.eurusd_fx AS B USING(Ticket);

DROP TABLE
IF EXISTS CumShort;

CREATE TABLE CumShort SELECT
    A.*
FROM
    ShortOrders AS A
JOIN `orders`.eurusd_fx AS B USING(Ticket);

SELECT DISTINCT
    A.*, CumLong.`Cumulative Long`,
    CumShort.`Cumulative Short`
FROM
    `orders`.eurusd_fx AS A
JOIN(CumShort, CumLong)ON(
    A.Ticket = CumLong.Ticket
    OR A.Ticket = CumShort.Ticket
) GROUP  BY A.`Open Time`;

输出：

+--------+---------------------+------+------+--------+---------------------+------------+-----------------+------------------+
| Ticket | Open Time           | Type | Size | Item   | Close Time          | Commission | Cumulative Long | Cumulative Short |
+--------+---------------------+------+------+--------+---------------------+------------+-----------------+------------------+
| 253199 | 2010-09-09 20:40:00 | sell |  0.1 | eurusd | 2010-09-09 20:41:00 | -0.89      |         0.10000 |          0.10000 |
| 255406 | 2010-09-13 19:30:00 | buy  |  0.1 | eurusd | 2010-09-14 04:30:00 | -0.9       |         0.10000 |          0.10000 |
| 258089 | 2010-09-15 07:00:00 | sell |  0.1 | eurusd | 2010-09-15 09:15:00 | -0.91      |         0.10000 |          0.10000 |
| 258197 | 2010-09-15 09:15:00 | buy  |  0.1 | eurusd | 2010-09-15 14:50:00 | -0.91      |         0.10000 |          0.10000 |
| 259659 | 2010-09-16 04:35:00 | sell |  0.1 | eurusd | 2010-09-16 18:35:00 | -0.91      |         0.10000 |          0.10000 |
| 261065 | 2010-09-17 07:05:00 | buy  |  0.1 | eurusd | 2010-09-20 00:02:00 | -0.92      |         0.10000 |          0.10000 |
| 262121 | 2010-09-20 03:00:00 | sell |  0.1 | eurusd | 2010-09-20 05:55:00 | -0.91      |         0.10000 |          0.10000 |
| 262192 | 2010-09-20 05:50:00 | buy  |  0.1 | eurusd | 2010-09-20 09:50:00 | -0.92      |         0.10000 |          0.10000 |
| 262739 | 2010-09-20 16:55:00 | sell |  0.1 | eurusd | 2010-09-20 18:45:00 | -0.91      |         0.10000 |          0.90000 |
| 262822 | 2010-09-20 18:40:00 | buy  |  0.1 | eurusd | 2010-09-21 02:05:00 | -0.92      |         0.10000 |          0.10000 |
| 263801 | 2010-09-21 13:05:00 | buy  |  0.1 | eurusd | 2010-09-21 21:25:00 | -0.92      |         0.40000 |          0.10000 |

它似乎无法正常工作。例如，第一个sell的累积长度应为0。

我真的很感激一些帮助！感谢。

编辑：还有一个问题：如何获得ABS(累积期长-累积空)的值？我需要NET累积位置大小。

3 个答案:

答案 0 :(得分：1)

这就是我理解你的要求的方式。如果有错，请澄清。

SELECT 
    A.Ticket AS Ticket,
    SUM(B.`Size`) AS `Cumulative Long`
FROM
    `orders`.eurusd_fx AS A
JOIN `orders`.eurusd_fx AS B ON (
    B.`Close Time` >= A.`Open Time`
    AND B.`Open Time` <= A.`Open Time`
    AND A.Type = B.Type
    AND A.Type = 'buy'
)
GROUP BY
    A.`Ticket`
ORDER BY
    A.`Ticket`;

答案 1 :(得分：1)

SELECT 
    A.*
  , SUM(CASE WHEN B.Type = 'buy'  THEN B.Size ELSE 0 END)
    AS `Cumulative Long`
  , SUM(CASE WHEN B.Type = 'sell' THEN B.Size ELSE 0 END) 
    AS `Cumulative Short`
FROM
  orders.eurusd_fx AS A
    JOIN
  orders.eurusd_fx AS B
      ON  B.`Open Time` <= A.`Open Time` 
      AND A.`Open Time` <= B.`Close Time` 
GROUP BY
    A.Ticket
ORDER BY
    A.`Open Time`
  , A.Ticket ;

或

SELECT 
    A.*
  , ( SELECT COALESCE(SUM(B.Size),0)
      FROM orders.eurusd_fx AS B
      WHERE B.`Open Time` <= A.`Open Time` 
        AND A.`Open Time` <= B.`Close Time` 
        AND B.Type = 'buy' 
    ) AS `Cumulative Long`
  , ( SELECT COALESCE(SUM(C.Size),0)
      FROM orders.eurusd_fx AS C
      WHERE C.`Open Time` <= A.`Open Time` 
        AND A.`Open Time` <= C.`Close Time` 
        AND C.Type = 'sell' 
    ) AS `Cumulative Short`
FROM
  orders.eurusd_fx AS A
ORDER BY
    A.`Open Time`
  , A.Ticket ;

要获得额外的计算，您可以添加另一个计算列或添加一个额外的图层（将ORDER BY推送到该外部图层）：

SELECT tmp.*
     , ABS(`Cumulative Long` - `Cumulative Short`) AS NetCumulativeSize 
FROM
  ( SELECT 
        A.*
      , SUM(CASE WHEN B.Type = 'buy'  THEN B.Size ELSE 0 END)
        AS `Cumulative Long`
      , SUM(CASE WHEN B.Type = 'sell' THEN B.Size ELSE 0 END) 
        AS `Cumulative Short`
    FROM
      orders.eurusd_fx AS A
        JOIN
      orders.eurusd_fx AS B
          ON  B.`Open Time` <= A.`Open Time` 
          AND A.`Open Time` <= B.`Close Time` 
    GROUP BY
        A.Ticket
  ) AS tmp
ORDER BY
    tmp.`Open Time`
  , tmp.Ticket ;

答案 2 :(得分：0)

我插入了不同票号的测试数据，不会改变程序。

SELECT DISTINCT A.*, CumLong.`Cumulative Long`, CumShort.`Cumulative Short` 

FROM `orders`.eurusd_fx AS A

LEFT JOIN Cumlong ON A.Ticket = CumLong.Ticket

LEFT JOIN cumshort ON A.Ticket = Cumshort.Ticket

GROUP BY A.`Open Time`

结果：

ticket open time   close time               type size Cumulative Long    Cumulative Short

1   2010-09-09 20:40:00  2010-09-09 20:41:00 sell 0.1 NULL               0.100000001490116

2   2010-09-13 19:30:00  2010-09-14 04:30:00 buy  0.1 0.100000001490116  NULL

3   2010-09-15 07:00:00  2010-09-15 09:15:00 sell 0.1 NULL               0.100000001490116

4   2010-09-15 09:15:00  2010-09-15 14:50:00 buy  0.1 0.100000001490116  NULL

5   2010-09-15 09:20:00  2010-09-15 14:50:00 buy  0.1 NULL               NULL

6   2010-09-16 04:35:00  2010-09-16 18:35:00 sell 0.1 NULL               0.100000001490116

7   2010-09-17 07:05:00  2010-09-20 00:02:00 buy  0.1 0.100000001490116  NULL

这就是你想要的？我不这么认为，因为唯一的订单打开而另一个打开也是258203.Nr 258197与258203同时关闭但是之前打开（我明白如果时间重叠你想要一个thar更早开始）

所以我猜结果应该是一行，订单258203，短期为0，.2？

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