我试图在asynctask中运行这些方法，因此它不会阻塞我的主UI。
有人可以举例说明如何做到这一点吗？
07-20 17:36:44.550: ERROR/AndroidRuntime(589): Caused by: android.view.ViewRoot$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.
public void getImages() throws IOException{
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpGet httppost = new HttpGet("https://sites.google.com/site/theitrangers/images/webImages.txt");
HttpResponse response;
response = httpclient.execute(httppost);
HttpEntity ht = response.getEntity();
BufferedHttpEntity buf = new BufferedHttpEntity(ht);
InputStream is = buf.getContent();
BufferedReader r = new BufferedReader(new InputStreamReader(is));
StringBuilder total = new StringBuilder();
String line;
while ((line = r.readLine()) != null) {
total.append(line + "\n");
imageUrl = total.toString();
}
}
public void getImage2() throws IOException{
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpGet httppost = new HttpGet("https://sites.google.com/site/theitrangers/images/webImage2.txt");
HttpResponse response;
response = httpclient.execute(httppost);
HttpEntity ht = response.getEntity();
BufferedHttpEntity buf = new BufferedHttpEntity(ht);
InputStream is = buf.getContent();
BufferedReader r = new BufferedReader(new InputStreamReader(is));
StringBuilder total = new StringBuilder();
String line;
while ((line = r.readLine()) != null) {
total.append(line + "\n");
imageUrl2 = total.toString();
}
}
public class ImageAdapter extends BaseAdapter {
/** The parent context */
private Context myContext;public ImageAdapter() {
// TODO Auto-generated constructor stub
}
/** URL-Strings to some remote images. */
private String[] myRemoteImages = {imageUrl,imageUrl2};
/** Simple Constructor saving the 'parent' context. */
public ImageAdapter(Context c) { this.myContext = c; }
public ImageAdapter(MyTask myTask) {
// TODO Auto-generated constructor stub
}
/** Returns the amount of images we have defined. */
public int getCount() { return this.myRemoteImages.length; }
/* Use the array-Positions as unique IDs */
public Object getItem(int position) { return position; }
public long getItemId(int position) { return position; }
/** Returns a new ImageView to
* be displayed, depending on
* the position passed. */
public View getView(int position, View convertView, ViewGroup parent) {
ImageView i = new ImageView(this.myContext);
try {
/* Open a new URL and get the InputStream to load data from it. */
URL aURL = new URL(myRemoteImages[position]);
URLConnection conn = aURL.openConnection();
conn.connect();
InputStream is = conn.getInputStream();
/* Buffered is always good for a performance plus. */
BufferedInputStream bis = new BufferedInputStream(is);
/* Decode url-data to a bitmap. */
Bitmap bm = BitmapFactory.decodeStream(bis);
bis.close();
is.close();
/* Apply the Bitmap to the ImageView that will be returned. */
i.setImageBitmap(bm);
} catch (IOException e) {
Log.e("DEBUGTAG", "Remtoe Image Exception", e);
}
/* Image should be scaled as width/height are set. */
i.setScaleType(ImageView.ScaleType.FIT_CENTER);
/* Set the Width/Height of the ImageView. */
i.setLayoutParams(new Gallery.LayoutParams(150, 150));
return i;
}
/** Returns the size (0.0f to 1.0f) of the views
* depending on the 'offset' to the center. */
public float getScale(boolean focused, int offset) {
/* Formula: 1 / (2 ^ offset) */
return Math.max(0, 1.0f / (float)Math.pow(2, Math.abs(offset)));
}
}
private class MyTask extends AsyncTask<Void, Void, Void>{
protected void onPreExecute(){
String imageUrl = null;
String imageUrl2 = null;
}
@Override
protected Void doInBackground(Void... arg0) {
try {
getImages();
getImage2();
} catch (IOException e) {
Log.e("MainMenu retreive image", "Image Retreival failed");
e.printStackTrace();
}
((Gallery) findViewById(R.id.gallery))
.setAdapter(new ImageAdapter(this));
return null;
}
}
}
答案 0 :(得分：1)
答案 1 :(得分：1)
您得到的错误是“只有创建视图层次结构的原始线程才能触及其视图。”
这个错误是因为你在另一个线程中处理UI，所以要解决这个问题，你只需要像这样更新UI。
Activityname.this.runOnUiThread(new Runnable() {
@Override
public void run() {
update the UI here......
}
});