java - 如何在没有集合的情况下对链表进行排序

Question

给定一个比较某种类型 T 的对象的比较器，我如何根据这种比较对我的链表进行排序？

这是我的链表的Link类的代码：

public class Link<T> {
    private T data;
    private Link<T> next;
    public Link(T data, Link<T> next){
        this.data = data;
        this.next = next;
    }
    public Link(T data){
        this(data, null);
    }
    public T getData(){
        return data;
    }
    public Link<T> getNext(){
        return next; 
    }
    public void setNext(Link<T> next){
        this.next = next;
    }
    public T setData(T data){
        T tmp = this.data;
        this.data = data; 
        return tmp;
    }
    public boolean equals(Object other) {  
        if(!(other instanceof Link<?>))
            return false;
        T otherData = ((Link<T>) other).data;
        return data.equals(otherData);
    }
    
    public String toString(){
        return data.toString();
    }

这里是 LinkedList 的类：

import java.util.Iterator;

public class LinkedList<T> implements List<T> {
    private Link<T> first;
    private Link<T> last;

    public LinkedList(){
        first = null;
        last = null;
    }

    public void sortBy(Comparator<T> comp){
        // Thats what Im trying to fill
        
    
    }
    

    public String toString() {
        String output = "[";
        for (Link<T> curr = first; curr!=null; curr=curr.getNext()) 
            output = output+curr.toString() + ", ";
        output = output+"]";
            
    return output;
            
    }
    

    public boolean equals(Object other) {  
        if (!(other instanceof LinkedList<?>))
            return false;
        LinkedList<T> otherList = (LinkedList<T>) other;
        if (size()!= otherList.size())
            return false;
        
        Iterator<T> IterA = iterator();
        Iterator<T> IterB = otherList.iterator();
        
        while (IterA.hasNext()) {
            if (!(IterA.next()).equals(IterB.next()))
                return false;   
        }
            
        return true;
        }
    
    public void add(int index, T element) {
        rangeCheck(index);
        nullCheck(element);
        if(index == 0) {
            first = new Link<T>(element, first) ;
            if(last == null)
                last = first ;
        } else {
            Link<T> prev = null ;
            Link<T> curr = first ;
            for(int i=0; i<index; i=i+1) {
                prev = curr ;
                curr = curr.getNext() ;
            }
            Link<T> toAdd = new Link<T>(element, curr);
            prev.setNext(toAdd);
            if(index == size())
                last = toAdd;
        }
    }

    public void add(T element) {
        nullCheck(element);
        if(isEmpty()){
            first = new Link<T>(element);
            last = first;
        }
        else {
            Link<T> newLast = new Link<T>(element);
            last.setNext(newLast);
            last = newLast;
        }
    }

    @Override
    public int size() {
        int counter = 0;
        for (Link<T> curr=first; curr!=null; curr=curr.getNext())
            counter++;
        return counter;
    }

    @Override
    public boolean contains(T element) {
        for (Link<T> curr = first; curr!=null; curr=curr.getNext() )
            if ((curr.getData()).equals(element))
                return true;
        return false;
    }

    @Override
    public boolean isEmpty() {
        if (first == null)
            return true;
        return false;
    }

    @Override
    public T get(int index) {
        rangeCheck(index);
        Link<T> curr = first;
        for (int i=index; i>0; i=i-1)
            curr=curr.getNext();
        return curr.getData();
    }

    @Override
    public T set(int index, T element) {
        rangeCheck(index);
        Link<T> curr = first;
        for (int i=index; i>0; i=i-1)
            curr=curr.getNext();
        T tmp = curr.getData();
        curr.setData(element);
        return tmp;
        
    }

    @Override
    public Iterator<T> iterator() {
        return new LinkedListIterator<T>(first);
        
    }

    // throws an exception if the given index is not in range
    private void rangeCheck(int index) {
        if(index < 0 || index >= size())
            throw new IndexOutOfBoundsException("Index: " + index + ", Size: " + size());
    }
    
    // throws an exception if the given element is null
    private void nullCheck(Object element){
        if (element == null)
            throw new NullPointerException();
    }

}

有没有有效的方法可以在没有集合的情况下对链表进行排序，并且只使用 LinkedList 类中的方法？ （不创建新数组或新链接）

我试图做的是使用带有函数“get(int index)”和“set(int index)”的while和for循环

但我正在寻找更有效的方法。

提前致谢。