我有一个数据框 df 如下
Number PT
5 AA
64 BB
7 CC
然后是另一个对象列表,
myList = [{'label': 'AA', 'value': 'AA', 'group': 'A'}, {'label': 'BB', 'value': 'BB', 'group': 'B'}]
我希望每个 PT 从列表中都有关联的组(如果可用),所以结果应该是这样的
Number PT group
5 AA A
64 BB B
7 CC NOT_MATCHED
答案 0 :(得分:0)
d = {'Number': [5, 64, 7], 'PT': ["AA", "BB", "CC"]}
df = pd.DataFrame(data=d)
myList = [{'label': 'AA', 'value': 'AA', 'group': 'A'}, {'label': 'BB', 'value': 'BB', 'group': 'B'}]
for i, row in df.iterrows():
for item in myList:
if item['value'] == df['PT'][i]:
df.at[i,'Group'] = item['group']
break
else:
df.at[i,'Group'] = "NOT_MATCHED"
答案 1 :(得分:0)
尝试:
df['group'] = df.PT.map({tuple(i.values())[0]: tuple(i.values())[
2] for i in myList}).fillna('Not Matched')