Question

我正在尝试编写一个代码，该代码从用户输入一行，将其拆分并将其提供给名为 counts 的 majestic 字典。一切都很好，直到我们向女王陛下询问一些数据。我希望数据的格式是首先打印单词并在其旁边打印重复的次数。下面是我设法编写的代码。

counts = dict()
print('Enter a line of text:')
line = input('')

words = line.split()

print('Words:', words)

print('Counting:')
for word in words:
    counts[word]  = counts.get(word,0) + 1
for wording in counts:
    print('trying',counts[wording], '' )

当它执行时，它的输出是不可原谅的。

Words: ['You', 'will', 'always', 'only', 'get', 'an', 'indent', 'error', 'if', 'there', 'is', 'actually', 'an', 'indent', 'error.', 'Double', 'check', 'that', 'your', 'final', 'line', 'is', 'indented', 'the', 'same', 'was', 'as', 'the', 'other', 'lines', '--', 'either', 'with', 'spaces', 'or', 'with', 'tabs.', 'Most', 'likely,', 'some', 'of', 'the', 'lines', 'had', 'spaces', '(or', 'tabs)', 'and', 'the', 'other', 'line', 'had', 'tabs', '(or', 'spaces).']
Counting:
trying 1 
trying 1 
trying 1 
trying 1 
trying 1 
trying 2 
trying 2 
trying 1 
trying 1 
trying 1 
trying 2 
trying 1 
trying 1 
trying 1 
trying 1 
trying 1 
trying 1 
trying 1 
trying 2

它只打印尝试和重复的次数，没有单词（我认为它在字典中被称为索引，如果我错了，请纠正我）

Thankyou

请帮助我，在回答这个问题时请记住我是一个新手，无论是python还是堆栈溢出。

Answer 1

在你的代码中没有任何地方试图打印这个词。您如何期望它出现在输出中？如果你想要这个词，把它放在要打印的东西列表中：

print(wording, counts[wording])

要了解更多信息，请查找包 collections，并使用 Counter 构造。

counts = Counter(words)

将为您计算所有字数。

Answer 2

您应该使用 counts.items() 迭代 counts 的键和值，如下所示：

counts = dict()
print('Enter a line of text:')
line = input('')

words = line.split()

print('Words:', words)

print('Counting:')
for word in words:
    counts[word]  = counts.get(word,0) + 1
for word, count in counts.items(): # notice this!
    print(f'trying {word} {count}')

另请注意，您可以在打印时使用 f 字符串。

Answer 3

我很困惑为什么要打印 trying。试试这个。

counts = dict()
print('Enter a line of text:')
line = input('')

words = line.split()

print('Words:', words)

print('Counting:')
for word in words:
    counts[word]  = counts.get(word,0) + 1
for wording in counts:
    print(wording,counts[wording], '' )

Answer 4

您拥有的代码遍历字典键并仅打印字典中的计数。你会想要做这样的事情：

for word, count in counts.items():
    print('trying', word, count)

您可能还想使用

from collections defaultdict
counts = defaultdict(lambda: 0)

所以在添加到字典时，代码会像

一样简单

counts[word] += 1

在python中打印字典值和键（索引）

4 个答案: