CREATE TABLE customers (
id SERIAL PRIMARY KEY,
order_date DATE,
customer VARCHAR(255)
);
INSERT INTO customers
(order_date, customer)
VALUES
('2020-05-10', 'user_01'),
('2020-05-15', 'user_01'),
('2020-05-18', 'user_02'),
('2020-05-26', 'user_03'),
('2020-06-03', 'user_04'),
('2020-06-05', 'user_05'),
('2020-06-24', 'user_06'),
('2021-05-02', 'user_01'),
('2021-05-05', 'user_01'),
('2021-05-12', 'user_03'),
('2021-05-20', 'user_07'),
('2021-06-08', 'user_04'),
('2021-06-20', 'user_06'),
('2021-06-21', 'user_08'),
('2021-06-25', 'user_08'),
('2021-06-25', 'user_09');
预期结果:
order_date | customer |
-------------|-------------|----
2021-05-02 | user_01 |
2021-05-05 | user_01 |
2021-05-12 | user_03 |
-------------|-------------|----
2021-06-08 | user_04 |
2021-06-20 | user_06 |
我想列出某个月份的所有客户
a) 在过去 12 个月没有存在并且
b) 在 12 个月之前已经存在。
对于一个月,我可以通过使用此查询来实现这一点:
SELECT
c1.order_date,
c1.customer
FROM customers c1
WHERE c1.order_date BETWEEN '2021-05-01 00:00:00' AND '2021-05-31 23:59:59'
/* Check if customer exists in the past 12 months */
AND NOT EXISTS
(SELECT
c2.customer
FROM customers c2
WHERE c2.order_date BETWEEN '2020-06-01 00:00:00' AND '2021-04-30 23:59:59'
AND c2.customer = c1.customer)
/* Check if customer exists before the past 12 months */
AND EXISTS
(SELECT
c2.customer
FROM customers c2
WHERE c2.order_date < '2020-06-01 00:00:00'
AND c2.customer = c1.customer)
ORDER BY 2;
但是,我必须每月单独运行此查询。
因此,我想知道是否有一个迭代解决方案可以一次经历几个月。
在上面的例子中,它会运行 BETWEEN '2021-05-01 00:00:00' AND '2021-06-30 23:59:59'
并计算从 5 月开始的 12 个月,在下一步中从 6 月开始 12 个月,以获得预期结果。
你知道这是否可行吗?
答案 0 :(得分:0)
SELECT
t1.order_date,
t1.customer
FROM
(SELECT
c.customer,
c.order_date,
LAG(c.order_date) OVER (PARTITION BY c.customer ORDER BY c.order_date) AS prev_order_date
FROM customers c) t1
WHERE t1.order_date BETWEEN '2021-05-01' AND '2021-06-30'
AND t1.prev_order_date >= date_trunc('month', t1.order_date) - interval '12 month'
AND t1.prev_order_date < date_trunc('month', t1.order_date)
ORDER BY 1,2;