在行动之前依靠反应钩子状态变化

时间:2021-05-12 14:17:16

标签: reactjs typescript react-hooks react-state react-state-management


我很难使用反应状态,需要你的帮助。

我正在使用自定义钩子来验证某种形式。
我每时每刻都在使用另一个钩子来控制系统状态。
问题是验证后,状态更新速度不够快。

我正在添加一个基本场景来举例说明我的问题。

MainComponent.tsx(表单)

import * as React from "react";

const MainComponent = () => {
  const [state1, setState1] = React.useState({});
  const [state2, setState2] = React.useState({});
  const {validateAll, errors} = userValidator(state1, state2)
  const {status} = useStatus(errors)

  const handleClick = () => {
    validateAll()
    console.log(status) // after validating, status is still not ok
    if (status === "ok") {
      runWhatEver()
    } else {
      console.log("getting in here :(")
      runAnotherThing()
    }
    console.log(status) // here its "ok" already
  }

  return (
    <div onClick={handleClick}>
    ....
    </div>
  );
}

useValidator.tsx

import * as React from "react";
import {validateState1, validateState2} from "validator.ts"

const userValidator = (state1, state2) => {
    const [state1Errors, setState1Errors] = useState<any>({});
    const [state2Errors, setState2Errors] = useState<any>({});

    const validateState1UsingValidator = (newValue) => {
      setState1Errors({
        state1: validateState1(state1)
      })
    }

    const validateState2UsingValidator = (newValue) => {
      setState2Errors({
        state1: validateState2(state2)
      })
    }

    const validateAll = () => {
      validateState1();
      validateState2();
    }

    return {validateAll, errors: {state1Errors, state2Errors}}
}

验证器.ts

export const validateState1 = (newValue) => {
  if (newValue.length <= 3) {
    return "valuelength  must be greater than 3";
  }
}

export const validateState2 = (newValue) => {
  if (newValue.length <= 3) {
    return "valuelength  must be greater than 3";
  }
}

useStatus.tsx

import * as React from "react";

const useStatus = (errors) => {

  const [status, setStatus] = useState("not ok");

  useEffect(() => {
    if (hasNoErrors()) {
      setStatus("ok")
    } else {
      setStatus("not ok")
    }
  }, [errors])

  return {status}
}

我知道状态更改是异步的,但是有什么方法可以让它按预期工作吗?
欢迎使用其他方法,但与实际问题相比,此演示微不足道,因此我不知道完全不同的方法是否可行。

非常感谢!

0 个答案:

没有答案