使用宏或公式,有没有办法实现以下Office 365公式的结果?
=FILTER(B:B,A:A = "x")
如果同一行上的 Column B
的值为 Column A
,它所做的是从 x
获取所有值。
我的电脑有 Office 365,但我使用的电脑只有 Office Pro Plus 2019
。当我需要这个功能时,我不得不使用我的电脑,我已经厌倦了,也许它也可以在 Office Pro Plus 2019 上使用公式或宏来完成?
答案 0 :(得分:3)
使用:
=IFERROR(INDEX($B$1:$B$100,AGGREGATE(15,7,ROW($A$1:$A$100)/($A$1:$A$100="x"),ROW($ZZ1))),"")
请注意使用设置的范围而不是完整的列。这是故意完成的,这是一个数组公式,它将对放置的每个单元格进行大量计算。将范围限制到数据集会加快速度。
将其放在输出的第一个单元格中并向下复制,直到返回空白。
答案 1 :(得分:2)
试试这个过滤函数的 UDF:
Function FILTER_HA(Where, Criteria, Optional If_Empty) As Variant
Dim Data, Result
Dim i As Long, j As Long, k As Long
'Create space for the output (same size as input cells)
With Application.Caller
i = .Rows.Count
j = .Columns.Count
End With
'Clear
ReDim Result(1 To i, 1 To j)
For i = 1 To UBound(Result)
For j = 1 To UBound(Result, 2)
Result(i, j) = ""
Next
Next
'Count the rows to show
For i = 1 To UBound(Criteria)
If Criteria(i, 1) Then j = j + 1
Next
'Empty?
If j < 1 Then
If IsMissing(If_Empty) Then
Result(1, 1) = CVErr(xlErrNull)
Else
Result(1, 1) = If_Empty
End If
GoTo ExitPoint
End If
'Get all data
Data = Where.Value
'Copy the rows to show
For i = 1 To UBound(Data)
If Criteria(i, 1) Then
k = k + 1
For j = 1 To UBound(Data, 2)
Result(k, j) = Data(i, j)
Next
End If
Next
'Return the result
ExitPoint:
FILTER_HA = Result
End Function
答案 2 :(得分:0)
我有一些空闲时间,我最近对用户定义的函数感兴趣,所以我决定制作我自己的版本,我想象的会是这样。我在开头说它不好,而且太长,但它有效!
Function JOINIF(ByRef IfRange As Range, ByVal Criteria As String, Optional JoinRange As Range, Optional Delimeter As String = ",") As String
'IfRange is the range that will be evaluated by the Criteria
'Criteria is a logical test that can be applied to a cell value.
'Examples of Criteria: "=Steve", ">100", "<>Toronto", "<=-1"
'JoinRange is the range of values that will be concatenated if the corresponding -
'IfRange cell meets the criteria. JoinRange can be left blank if the values to be -
'concatenated are the IfRange values.
'Delimeter is the string that will seperate the concatenated values.
'Default delimeter is a comma.
Dim IfArr() As Variant, JoinArr() As Variant, OutputArr() As String
Dim IfArrDim As Integer, JoinArrDim As Integer
Dim JCount As Long, LoopEnd(1 To 2) As Long
Dim MeetsCriteria As Boolean, Expression As String
Dim Regex As Variant, Matches As Variant
'PARSING THE CRITERIA
'Add Regular Expressions as a VBA referrence
AddRef ThisWorkbook, "{3F4DACA7-160D-11D2-A8E9-00104B365C9F}", "VBScript_RegExp_55"
Set Regex = CreateObject("VBScript.RegExp")
Regex.Pattern = "[=<>]+"
'Looking for comparison operators
Set Matches = Regex.Execute(Criteria)
If Matches.Count = 0 Then
'If no operators found, assume default "Equal to"
If Not IsNumeric(Criteria) Then
'Add quotation marks to allow string comparisons
Criteria = "=""" & Criteria & """"
End If
Else
If Not IsNumeric(Replace(Criteria, Matches(0), "")) Then
Criteria = Matches(0) & """" & Replace(Criteria, Matches(0), "") & """"
End If
'Add quotation marks to allow string comparisons
End If
'Default option for optional JoinRange input
If JoinRange Is Nothing Then Set JoinRange = IfRange
'DIMENSIONS
'Filling the arrays
If IfRange.Cells.Count > 1 Then
IfArr = IfRange.Value
IfArrDim = Dimensions(IfArr)
Else
ReDim IfArr(1 To 1)
IfArr(1) = IfRange.Value
IfArrDim = 1
End If
If JoinRange.Cells.Count > 1 Then
JoinArr = JoinRange.Value
JoinArrDim = Dimensions(JoinArr)
Else
ReDim JoinArr(1 To 1)
JoinArr(1) = JoinRange.Value
JoinArrDim = 1
End If
'Initialize the Output array to the smaller of the two input arrays.
ReDim OutputArr(IIf(IfRange.Cells.Count < JoinRange.Cells.Count, IfRange.Cells.Count - 1, JoinRange.Cells.Count - 1))
'DEFINING THE LOOP PARAMETERS
'Loop ends on the smaller of the two arrays
If UBound(IfArr) > UBound(JoinArr) Then
LoopEnd(1) = UBound(JoinArr)
Else
LoopEnd(1) = UBound(IfArr)
End If
If IfArrDim = 2 Or JoinArrDim = 2 Then
If Not (IfArrDim = 2 And JoinArrDim = 2) Then
'mismatched dimensions
LoopEnd(2) = 1
ElseIf UBound(IfArr, 2) > UBound(JoinArr, 2) Then
LoopEnd(2) = UBound(JoinArr, 2)
Else
LoopEnd(2) = UBound(IfArr, 2)
End If
End If
'START LOOP
If IfArrDim = 1 Then
For i = 1 To LoopEnd(1)
If IsNumeric(IfArr(i)) And IfArr(i) <> "" Then
Expression = IfArr(i) & Criteria
Else
'Add quotation marks to allow string comparisons
Expression = """" & IfArr(i) & """" & Criteria
End If
MeetsCriteria = Application.Evaluate(Expression)
If MeetsCriteria Then
If JoinArrDim = 1 Then
OutputArr(JCount) = CStr(JoinArr(i))
Else
OutputArr(JCount) = CStr(JoinArr(i, 1))
End If
JCount = JCount + 1
End If
Next i
Else
For i = 1 To LoopEnd(1)
For j = 1 To LoopEnd(2)
If IsNumeric(IfArr(i, j)) And IfArr(i, j) <> "" Then
Expression = IfArr(i, j) & Criteria
Else
'Add quotation marks to allow string comparisons
Expression = """" & IfArr(i, j) & """" & Criteria
End If
MeetsCriteria = Application.Evaluate(Expression)
If MeetsCriteria Then
If JoinArrDim = 1 Then
OutputArr(JCount) = CStr(JoinArr(i))
Else
OutputArr(JCount) = CStr(JoinArr(i, j))
End If
JCount = JCount + 1
End If
Next j
Next i
End If
'END LOOP
ReDim Preserve OutputArr(JCount + 1 * (JCount > 0))
JOINIF = Join(OutputArr, Delimeter)
End Function
Private Sub AddRef(wbk As Workbook, sGuid As String, sRefName As String)
'Credit for this Sub goes to the great @hennep from StackOverflow
Dim i As Integer
On Error GoTo EH
With wbk.VBProject.References
For i = 1 To .Count
If .Item(i).Name = sRefName Then
Exit For
End If
Next i
If i > .Count Then
.AddFromGuid sGuid, 0, 0
' 0,0 should pick the latest version installed on the computer
End If
End With
EX: Exit Sub
EH: MsgBox "Error in 'AddRef'" & vbCrLf & vbCrLf & Err.Description
Resume EX
Resume ' debug code
End Sub
Private Function Dimensions(var As Variant) As Long
'Credit goes to the great Chip Pearson, chip@cpearson.com, www.cpearson.com
On Error GoTo Err
Dim i As Long, tmp As Long
While True
i = i + 1
tmp = UBound(var, i)
Wend
Err:
Dimensions = i - 1
End Function
使用示例:
将 IfRange 和 JoinRange 分开
IfRange 作为 JoinRange
答案 3 :(得分:0)
您可以尝试以下 udf(示例调用:FILTER2(A1:A100,B1:B100)
),其中包含以下棘手的步骤:
=If(A1:A100="x",Row(A1:A100),"?"
) 作为表格 Excel 公式并将所有有效行号分配给数组 x
(用“?”字符串标记其余部分),Application.Index()
的数据列应用 x
Public Function Filter2(rng1 As Range, rng2 As Variant, Optional ByVal FilterID As String = "x")
Dim a As String: a = rng1.Address(False, False, External:=True)
'a) get all valid row numbers (rng1)
Dim myformula As String: myformula = "if(" & a & "=""" & FilterID & """,row(" & a & "),""?"")"
Dim x: x = Application.Transpose(Evaluate(myformula))
'b) filter out invalid "?" elements
x = VBA.Filter(x, "?", False)
'c) apply x upon data column (rng2)
If UBound(x) > -1 Then Filter2 = Application.Index(rng2, Application.Transpose(x), 1)
End Function
注意 2019/MS 365 版本之前的函数调用需要输入为数组公式 (Ctrl+Shift+Enter)。
该函数采用一列(范围)参数。