如何删除列表中的特定值？

Question

如何删除列表中的特定值？

列表的值存在。

review_list = ["14hour","16hour","20hour","24hour","8hour","4hour","2hour","hello","jae12"]

如果您查看列表值，

只有数值在 int(1-24) 小时之前发生变化。

如何删除 int (1-24)hour 并输出剩余的值？

输出

review_list = "hello","jae12"]

Answer 1

根据您的预期输出，您想要删除值中包含“小时”的元素

review_list = ["14hour","16hour","20hour","24hour","8hour","4hour","2hour","hello","jae12"]
review_filtered = [x for x in review_list if "hour" not in x]

输出

["hello", "jae12"]

Answer 2

review_list = list(filter(lambda item: not item.endswith("hour"), review_list))

或

import re
review_list = list(filter(lambda item: not re.match('^[0-9]+hour$',item), review_list))