我有输入字段(名称:day1和varchar)以在我的表单中输入日期。它附有一个jquery日历,并以“D,dd M,yy”格式选择日期(我想要点这个并且不能改变格式)。我想转换并保存到mysql日期格式到表中。这怎么可能?
$insert_query = 'insert into '.$this->tablename.'(
venue,
day1,
day2,
day3,
day4,
day5,
day6,
day7,
day8,
day9,
day10,
city,
contactperson,
)
values
(
"' . $this->SanitizeForSQL($formvars['venue']) . '",
"' . $this->SanitizeForSQL($formvars['day1']) . '",
"' . $this->SanitizeForSQL($formvars['day2']) . '",
"' . $this->SanitizeForSQL($formvars['day3']) . '",
"' . $this->SanitizeForSQL($formvars['day4']) . '",
"' . $this->SanitizeForSQL($formvars['day5']) . '",
"' . $this->SanitizeForSQL($formvars['day6']) . '",
"' . $this->SanitizeForSQL($formvars['day7']) . '",
"' . $this->SanitizeForSQL($formvars['day8']) . '",
"' . $this->SanitizeForSQL($formvars['day9']) . '",
"' . $this->SanitizeForSQL($formvars['day10']) . '",
"' . $this->SanitizeForSQL($formvars['city']) . '",
"' . $this->SanitizeForSQL($formvars['contactperson']) . '",
)';
第1天到第10天是要转换的日期...
答案 0 :(得分:1)
在日期输入中尝试此操作:
$date = date('Y-m-d H:i:s', strtotime($_GET['date_input']));
只要strtotime()
从您的输入中选择正确的时间戳,您就可以了。不要忘记逃避它。
答案 1 :(得分:0)
或在sql语句中,您可以这样做:
$insert_query = 'insert into '.$this->tablename.'(
venue,
day1,
day2,
day3,
(.......) )
values
("' . $this->SanitizeForSQL($formvars['venue']) . '",
STR_TO_DATE("' . $this->SanitizeForSQL($formvars['day1']) . '","%W, %d %M, %y"),
STR_TO_DATE("' . $this->SanitizeForSQL($formvars['day2']) . '","%W, %d %M, %y"),
STR_TO_DATE("' . $this->SanitizeForSQL($formvars['day1']) . '","%W, %d %M, %y"),
(.......) )';
“%W,%d%M,%y”位的格式必须与日历中的日期格式相同...
要查看所有日期函数和日期格式,请参阅以下链接:
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_str-to-date
我希望有帮助...