Question

我想搜索完整的字符串或字符串的一部分是否是数组的一部分。如何在PHP中实现这一目标？

另外，我如何在其中使用metaphone？

示例：

array1={'India','USA','China'};
array2={'India is in east','United States of America is USA','Made in China'}

如果我在array1中搜索array2，则：

'印度'应与“印度在东方”相匹配，同样适用于美国和美国。中国。

Answer 1

$array1 = array('India','USA','China');
$array2 = array('India is in east','United States of America is USA','Made in China');
$found = array();

foreach ($array1 as $key => $value) {
    // Thanks to @Andrea for this suggestion:
    $found[$value] = preg_grep("/$value/", $array2);
    // Alternative:
    //$found = $found + preg_grep("/$value/", $array2);
}

print_r($found);

结果：

Array
(
    [0] => India is in east
    [1] => United States of America is USA
    [2] => Made in China
)

使用Metaphone比较棘手。您必须确定匹配的内容。一种方法是使用Methaphone结果之间的Levenshtein距离来比较两个值。

更新：请参阅@Andrea's解决方案，了解更为明智的单词Metaphone比较。

这是一个粗略的例子：

$meta1 = array_map(
    create_function( '$v', 'return array(metaphone($v) => $v);' ),
    $array1
);

$meta2 = array_map(
    create_function( '$v', 'return array(metaphone($v) => $v);' ),
    $array2
);

$threshold = 3;

foreach ($meta2 as $key2 => $value2) {

    $k2 = key($value2);
    $v2 = $value2[$k2];

    foreach ($meta1 as $key1 => $value1) {

        $k1  = key($value1);
        $v1  = $value1[$k1];
        $lev = levenshtein($k2, $k1);

        if( strpos($v2, $v1) !== false || levenshtein($k2, $k1) <= $threshold ) {
            array_push( $found, $v2 );
        }
    }
}

......但它需要工作。如果阈值太高，它会产生重复。您可能更喜欢两次通过比赛。一个用于查找简单匹配，如在我的第一个代码示例中，然后另一个用于匹配Metaphone，如果第一个没有匹配。

Answer 2

metaphone案例也可能遵循Mike针对严格案例提出的相同结构。

我认为不需要额外的相似性功能，因为metaphone的目的应该是给我们一个听起来相同的词的常用键。

$array1 = array('India','USA','China');
$array2 = array(
    'Indiuh is in east',
    'United States of America is USA',
    'Gandhi was born in India',
    'Made in China'
);
$found = array();
foreach ($array1 as $key => $value) {
    $found[$value] = preg_grep('/\b'.$value.'\b/i', $array2);
}

var_export($found);

echo "\n\n";

function meta( $sentence )
{
    return implode(' ', array_map('metaphone', explode(' ', $sentence)));
}

$array2meta = array_map('meta', $array2);
foreach ($array1 as $key => $value) {
    $valuemeta = meta($value);
    $foundmeta[$value] = preg_grep('/\b'.$valuemeta.'\b/', $array2meta);
    $foundmeta[$value] = array_intersect_key($array2, $foundmeta[$value]);
}

var_export($foundmeta);

上面的代码打印出来：

array (
  'India' => 
  array (
    2 => 'Gandhi was born in India',
  ),
  'USA' => 
  array (
    1 => 'United States of America is USA',
  ),
  'China' => 
  array (
    3 => 'Made in China',
  ),
)

array (
  'India' => 
  array (
    0 => 'Indiuh is in east',
    2 => 'Gandhi was born in India',
  ),
  'USA' => 
  array (
    1 => 'United States of America is USA',
  ),
  'China' => 
  array (
    3 => 'Made in China',
  ),
)

Answer 3

$a1 = array('India','USA','China');
$a2 = array('India is in east','United States of America is USA','Made in China');


foreach ( $a2 as $a )
{
  foreach( $a1 as $b  )
  {
    if ( strpos( $a, $b ) > -1 )
    {
      echo $a . " contains " . $b . "\n";
    }
  }
}

如何在数组中搜索字符串的一部分？

3 个答案: