如何使用AJAX或类似方法编辑内联MySQL查询的结果?

时间:2011-07-19 03:07:22

标签: php mysql ajax forms inline-editing

我正在使用PHP将使用<div>从MySQL查询生成的表注入到混合的HTML / PHP文件中。 <div>index.php中声明<div id="searchdiv"></div>,如此:<div>

<form id="searchform"> <td class="master">Codigo o nombre cliente: <input type="text" name="box" onkeypress="return noenter()" /><input id="srchsubmit" type="submit" value="Buscar" onclick="showUser(this.form['box'].value);return false;" /><br /></td></form> 的内容生成如下:

(1)创建搜索框:

function showUser(str){
    if (str==""){
        document.getElementById("searchdiv").innerHTML="";
        return;
        }
        if (window.XMLHttpRequest){
            // code for IE7+, Firefox, Chrome, Opera, Safari
            xmlhttp=new XMLHttpRequest();
            }
            else
            {
                // code for IE6, IE5
                xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
                }
                xmlhttp.onreadystatechange=function(){
                    if (xmlhttp.readyState==4 && xmlhttp.status==200){
                        document.getElementById("searchdiv").innerHTML=xmlhttp.responseText;
                        }
                        }
                        xmlhttp.open("GET","search.php?q="+str,true);
                        xmlhttp.send();
                        }

(2)执行JavaScript:

<div>

(3)构造结果以注入<?php // Fetch the string from the search box $q=$_GET["q"]; // Connection settings $dbhost = "localhost"; $dbuser = "root"; $dbpass = ""; $dbname = "scorecard"; //Connect to MySQL Server mysql_connect($dbhost, $dbuser, $dbpass); //Select Database mysql_select_db($dbname) or die(mysql_error()); // Fetch data $sql="SELECT * FROM scoreboard WHERE codcliente = '".$q."' OR lower(nombre) LIKE '%".strtolower($q)."%'"; $result = mysql_query($sql); if(mysql_num_rows($result) == 0){ echo '<div align="center" style="background-color:#CCCCCC; font-weight:bold; color:#C0504D;">Record no existe.&nbsp;&nbsp;&nbsp;<input id="srchcreate" type="button" value="Crear" /></div>'; return; } //echo $result; // Construct the table echo "<table id='srchtable' class='srchtable'>"; // Construct the array while($row = mysql_fetch_array($result)){ echo "<tr>"; echo "<td align='center'>" . $row['codcliente'] . "</td>"; echo "<td align='left'>" . $row['nombre'] . "</td>"; // echo "<td align='center'>" . $row['ejecutivo'] . "</td>"; // echo "<td align='center'>" . $row['banca_as400'] . "</td>"; // echo "<td align='center'>" . $row['banca_real'] . "</td>"; // echo "<td align='right'>" . $row['ingresos'] . "</td>"; echo "<td align='center'>" . $row['ciiu'] . "</td>"; // echo "<td align='center'>" . $row['division'] . "</td>"; echo "<td align='left'>" . $row['actividad'] . "</td>"; echo "<td align='center' class='{$row['riesgo_industria']}'>" . $row['riesgo_industria'] . "</td>"; echo "<td align='center' class='{$row['riesgo_cliente']}'>" . $row['riesgo_cliente'] . "</td>"; echo "<td align='center'>" . $row['fecha'] . "</td>"; echo "<td align='center'>" . $row['analista'] . "</td>"; echo "<td align='center'>" . "<input id='edit' type='button' value='Editar' onclick='' />" . "</td>"; echo "</tr>"; } echo "</table>"; ?>

<td>

结果如下所示:Screenshot。我的问题是,当我点击“Editar”(编辑)按钮时,如何使字段可以在线编辑?也许在{{1}}的前面放置一个选项输入来选择要编辑的行?编辑后,如何将更改插入MySQL?谢谢!

1 个答案:

答案 0 :(得分:1)

对于你的第一个问题,你不需要复选框。如果你不介意jquery,你可以使用

$(this).closest('tr')

获取单击的编辑按钮所在的行。然后,您可以使用输入替换要编辑的每个单元格的内容。将表格换成表格标签并使用ajax提交。

让你入门的东西......

$(document).ready(function(){
        $(".edit").click(function(){
            var tr = $(this).closest("tr");
            var submit = "<input type='submit' name='Submit' value='Submit' />";

            tr.find(".td").each(function(){
                var name = $(this).attr("title");
                var value = $(this).html();
                var input = "<input type='text' name='"+name+"' value='"+value+"' />";
                $(this).html(input);
            });

            tr.find(".button").html(submit);

        });
    });

假设您的表/表格看起来像:

<form id="form" name="form" action="#">
        <table>
            <tr class="row">
                <td class="td" title="first_name">John</td>
                <td class="td" title="last_name">Smith</td>
                <td class="button" title="button"><button class="edit">Edit</button></td>
            </tr>
            <tr class="row">
                <td class="td" title="first_name">Roger</td>
                <td class="td" title="last_name">Jones</td>
                <td class="button" title="button"><button class="edit">Edit</button></td>
            </tr>
        </table>
    </form>

然后,您需要执行ajax提交并删除输入/恢复为文本。