Question

我的问题与此处相同：https://github.com/tongyy/react-native-draggable/issues/92 反正我重新写：用法：我使用 draggable 在故事中创建贴纸。因为我可以有 1 个以上的贴纸，所以我将它们放在一个数组中，然后用一个按钮推动贴纸。预期行为：当你移动贴纸（onDragRelease）时，我应该取贴纸的位置并在状态上更新它，但我不能取贴纸属性的绝对位置，因为在我释放拖动后，贴纸随机变化。我尝试使用 locationX、pageX（分别使用 Y）但仍然做同样的事情。

constructor(props) {
        super(props);

        const stickers = [];

        const textStickers = [];

        this.state = { textStickers };
        this.state = { stickers };
}

当我按下添加按钮时（添加贴纸的功能）：

let last = this.state.stickers.length;
this.setState(prevState => ({
  stickers: [...prevState.stickers, {
    id: last + 1,
    uri: "https://cataas.com/cat/says/" + last + 1,
    x: Dimensions.get('window').width / 2 - 75,     //I put the new sticker on the center X
    y: Dimensions.get('window').height / 2 - 75,   //I put the new sticker on the center Y
    size: 150
  }]
}))

以及不起作用的位置函数：

onDragRelease={
    (bounds) => {
        this._changeFace
        console.log("This sticker has id: " + sticker.id)
        //Current sticker array
        var array = this.state.stickers
        //The new array
        var newArray = []
        //I use for to run the array and find the value I want to update (Based on ID)
        for (let i = 0; i < array.length; i++) {
            //If the ID is not the one on this sticker I just add it (push) with no changes
            if (array[i].id !== sticker.id) {
                newArray.push(array[i])
            } 
            else //If this is the sticker, I edit the sticker on the array with i and just add it after editin
            {
                //First add it to the new array to avoid modifying the state without setState
                newArray.push(array[i])
                /*
                ! Now make the changes. Here you see I tried the solution of 
                ! https://stackoverflow.com/questions/55529217/react-native-get-x-and-y-coordinates-of-draggable-object-using-panresponder-pan
                ! with no success, but also tried with only page, with only location and any single solution I thought could be the one.
                */
                newArray[i].x = bounds.nativeEvent.pageX - bounds.nativeEvent.locationX             //!BUG!
                newArray[i].y = bounds.nativeEvent.pageY - bounds.nativeEvent.locationY             //!BUG!
            }
        }
        //Finally I update the changes putting newArray in the state
        this.setState({
            stickers: newArray
        })
    }
}

我希望每当我更新位置（拖动）时，我的状态中的位置都会发生变化，然后更新组件以使贴纸数组保持不变

反应原生绝对位置在反应原生可拖动中不起作用

0 个答案: