我为条纹制作了一个 webhook（烧瓶）。
我的应用既有一次性付款又有订阅。
我想知道如何检测是正常结帐还是订阅？
这就是我现在分离的方式，但我认为这是不推荐的方式。
我正在检查 stripe_subscription_id，如果存在，我将其视为订阅。
（charge.succeeded 也调用订阅成功）
@api.route('/stripe/webhook', methods=['GET', 'POST'])
def webhook():
event = None
payload = request.data
try:
event = json.loads(payload)
except Exception as e:
print('Webhook error while parsing basic request.' + str(e))
if not event:
return jsonify({'status': 'failed'}), 400
# one time payout
if event['type'] == 'charge.succeeded':
event_intent = event['data']['object']
payment_intent = event_intent['payment_intent']
# payment
if event['type'] == 'checkout.session.completed':
checkout_session = event['data']['object']
stripe_subscription_id = checkout_session['subscription']
# customer_email = checkout_session['customer_email']
if stripe_subscription_id:
# Create a new subscription and mark it as paid this month.
customer_subscription_mark_paid(checkout_session['id'], stripe_subscription_id)
elif event['type'] == 'invoice.paid':
invoice = event['data']['object']
stripe_subscription_id = invoice['subscription']
if stripe_subscription_id:
# Check if this is the first invoice or a later invoice in the
# subscription lifecycle.
first_invoice = invoice['billing_reason'] == 'subscription_create'
# You already handle marking the first invoice as paid in the
# `checkout.session.completed` handler.
# Only use this for the 2nd invoice and later, so it doesn't conflict.
if not first_invoice:
# Mark the subscription as paid.
customer_subscription_mark_paid(None, stripe_subscription_id)
elif event['type'] == 'invoice.payment_failed':
invoice = event['data']['object']
stripe_subscription_id = invoice['subscription']
if stripe_subscription_id:
customer_subscription_mark_past_due(None, stripe_subscription_id)