我很难解释这个,但我希望一些代码可以提供帮助:
var softChannels = channels.ByPath("/software/").Children.Where(c => c.StateProperties.IsActive);
var tmpGames = new List<MyCms.Content.Games.Game>();
// Get games only from active game channels
foreach (var channel in channels.ByPath("/gameslivecasinodirectcom/game-channels/").Children.Where(c => c.StateProperties.IsActive))
{
// QUESTION IS ABOUT THIS LINE
tmpGames.AddRange(oGames.AllActive.Where(g => g.StateProperties.Channels.Contains(channel.Guid) && g.GamingProperties.Software.Contains(softChannels)));
}
我想要做的是,如果g.GamingProperties.Software
包含其中一个softChannel之一,则添加它。也许一个不同的认可会更好......任何建议?
p.s我知道这行不起作用,我把代码放在那里只是为了便于理解我需要的东西。
编辑: 我想我已经解决了它:
var softChannels = channels.ByPath("/software/").Children.Where(c => c.StateProperties.IsActive).Select(c => c.Guid);
var tmpGames = new List<MyCms.Content.Games.Game>();
// Get games only from active game channels
foreach (var channel in channels.ByPath("/gameslivecasinodirectcom/game-channels/").Children.Where(c => c.StateProperties.IsActive))
{
tmpGames.AddRange(oGames.AllActive.Where(g => g.StateProperties.Channels.Contains(channel.Guid) && softChannels.Contains(g.GamingProperties.Software.Trim())));
}
如果有人发现错误,请告诉我。
答案 0 :(得分:6)
您想要检查Any()
的{{1}}是否包含在内:
softChannels
事实上,你甚至可以写
softChannels.Any(sc => g.GamingProperties.Software.Contains(sc))