class Lists extends \Entities\AbstractEntity {
/**
* @Id @Column(name="id", type="bigint",length=15)
* @GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @ManyToMany(targetEntity="\Entities\Users\Usercomments")
* @JoinColumn(name="id", referencedColumnName="id")
*/
protected $comments;
public function getComments() {
return $this->comments;
}
public function addComments($comment) {
$this->comments->add($comment);
}
public function deleteComments(\Entities\Users\Comments $comments) {
$this->comments->removeElement($comments);
}
/** @PreUpdate */
public function updated() {
//$this->updated_at = new \DateTime("now");
}
public function __construct() {
$this->entry = new \Doctrine\Common\Collections\ArrayCollection();
}
}
我有一个由学说创建的多对多表格。我可以设法通过以下方式为此表添加评论:
$getList = $this->_lis->findOneBy((array('userid' => $userid)));
$getComments = $this->_doctrine->getReference('\Entities\Users\Comments', $commentid);
$getList->addComments($getComments);
$this->_doctrine->flush();
但我不能删除... 我试过:removeElement但没有快乐.. 有人告诉我,我可以在我的阵列集合中解开soemthing,我不明白......
答案 0 :(得分:-1)
你可以使用一个简单的PHP" unset()"在ArrayCollection元素上。最好的方法是在Entity类中定义一个新方法。
这是一个从ArrayCollection属性中删除所有元素的示例:
/**
* Goes into your Entity class
* Refers to property Entity::widget
* @return $this
*/
public function removeAllWidgets()
{
if ($this->widget) {
foreach ($this->widget as $key => $value) {
unset($this->widget[$key]);
}
}
return $this;
}
您可能还可以定义一个Entity方法来删除单个元素:
/**
* Goes into your Entity class
* @param int $elementId
* @return $this
*/
public function removeOnewidget($elementId)
{
if (isset($this->widget[$elementId])) {
unset($this->widget[$elementId]);
}
return $this;
}