Question

我正在以模态方式呈现ViewController。如何访问父视图控制器？

我的架构是TabBarController =＆gt; VC1 =＆gt; VC2 =＆gt; VC3 =＆gt; MVC1，我想从MVC1到达VC3。

在VC3中，我有这段代码：

- (void) editAd{
    AskPasswordViewController *modalViewController = [[AskPasswordViewController alloc] initWithNibName:@"AskPasswordView" bundle:nil];

    NSLog(@"modalparent class=%@", [[modalViewController parentViewController] class]);

    [self presentModalViewController:modalViewController animated:YES];
    [modalViewController release];
}

我在MVC1中试过这个：

- (void) sendRequest {
    NSLog(@"classe : %@",[[self parentViewController] class] );
}

但它返回我的TabBarViewController ...

Answer 1

您可以通过以下方式访问父级：

self.presentingViewController

根据苹果文档：

提供此视图控制器的视图控制器（或其视图控制器）最远的祖先。）

Answer 2

我这样做的方法就是简单地创建一个委托。在AskPasswordViewController的标题中，输入

id delegate;

和

@property (nonatomic, assign) id delegate;

在实现文件中合成它。然后在分配/初始化模态控制器之后，在呈现它之前，设置modalViewController.delegate = self;。然后在模态控制器中，您可以调用self.delegate从呈现它的视图控制器获取信息。我希望这有帮助

Answer 3

你可以通过调用parentViewController来改进：

self.parentViewController.parentViewController ....等等，直到你找到合适的人。

Answer 4

除了Vibhor Goyal - 有时，self.presentingViewController注册为NavigationController。因此，试试：

if let vc = self.presentingViewController.childViewControllers.last as? YourViewController {
// do stuff here
}

Answer 5

在这里，我提出了从任何地方导航到根目录的通用方法。

您使用此类创建一个新的类文件，以便可以从项目的任何位置访问它：

import UIKit

class SharedControllers
{
    static func navigateToRoot(viewController: UIViewController)
    {
        var nc = viewController.navigationController

        // If this is a normal view with NavigationController, then we just pop to root.
        if nc != nil
        {
            nc?.popToRootViewControllerAnimated(true)
            return
        }

        // Most likely we are in Modal view, so we will need to search for a view with NavigationController.
        let vc = viewController.presentingViewController

        if nc == nil
        {
            nc = viewController.presentingViewController?.navigationController
        }

        if nc == nil
        {
            nc = viewController.parentViewController?.navigationController
        }

        if vc is UINavigationController && nc == nil
        {
            nc = vc as? UINavigationController
        }

        if nc != nil
        {
            viewController.dismissViewControllerAnimated(false, completion:
                {
                    nc?.popToRootViewControllerAnimated(true)
            })
        }
    }
}

从项目的任何位置使用：

{
    ...
    SharedControllers.navigateToRoot(self)
    ...
}

Answer 6

//You have to get the root, iterate through the root's ViewControllers and then ask for the ParentViewController.
    UINavigationController *root = (UINavigationController*)[[(AppDelegate*) [[UIApplication sharedApplication]delegate] window] rootViewController];
           for (UIViewController *VC in root.viewControllers) {
               if([VC isKindOfClass:[YourParentViewController class]]){
                   YourParentViewController*  parent = (YourParentViewController*)VC;
                   [parent callMethod]; // your code here
                   [self dismissViewControllerAnimated:YES completion:nil];
               }
           }

Answer 7

如果 class PropertiesJavaFormatConfig implements JavaFormatConfig { private final Properties properties; PropertiesJavaFormatConfig(Properties properties) { this.properties = properties; } @Override public IndentationStyle getIndentationStyle() { Object value = this.properties.get("indentation-style"); return (value != null) ? IndentationStyle.valueOf(value.toString().toUpperCase().trim()) : DEFAULT.getIndentationStyle(); } static JavaFormatConfig load(File file) throws IOException { try (InputStream inputStream = new FileInputStream(file)) { return load(inputStream); } } static JavaFormatConfig load(InputStream inputStream) throws IOException { Properties properties = new Properties(); properties.load(inputStream); return new PropertiesJavaFormatConfig(properties); } } 给了您意想不到的结果并且您不想摆弄它，请执行以下操作：

presentingViewController

访问模态视图控制器父级

7 个答案: