Question

基本上，我的 Discord 机器人中有一个反脏话系统，其中一个列入黑名单的词是“锄头”。但是，如果您说的单词包含脏话，例如“whoever”，则机器人会将其检测为脏话，因为它会在其中找到“hoe”一词。

如何在不从黑名单中删除“锄头”一词的情况下防止这种情况发生？

这是我的代码：

@client.event
async def on_message(message):
    if message.author.bot:
        return
    for badword in file:
        if badword in message.content.lower():
            await message.delete()
            warnMessage = f"Hey {message.author.mention}! Don't say that!"
            await message.channel.send(warnMessage, delete_after=5.0)
            print(f"{message.author.name} tried saying: {badword}")
            channel = client.get_channel(836232733126426666)
            
            embed = discord.Embed(title=f"Someone tried to swear!", colour=0x2D2D2D)
            embed.add_field(name="Person who tried to swear:", value=f"{message.author.name}", inline=False)
            embed.add_field(name="What they tried to say:", value=f"{badword}", inline=False)
            embed.add_field(name="Channel they tried to swear in:", value=f"<#{message.channel.id}>", inline=False)
            
            await channel.send(embed=embed)
            return
            await client.process_commands(message)
            
    if message.content.startswith('Jason derulo'):
        await message.channel.send('Wiggle wiggle wiggle')
        
    if message.content.startswith('fast'):
        await message.channel.send('She a runner she a track star')
    await client.process_commands(message)
    
@client.event
async def on_message_edit(before, after):
    for badword in file:
        if badword in after.content.lower():
            await after.delete()
            warnMessage = f"Hey {after.author.mention}! Don't say that!\n*You said ||{badword}||*"
            await after.channel.send(warnMessage, delete_after=5.0)
            print(f"{message.author.name} tried saying: {badword}")
            channel = client.get_channel(836232733126426666)
            
            embed = discord.Embed(title=f"Someone tried to swear!", colour=0x2D2D2D)
            embed.add_field(name="Person who tried to swear:", value=f"{message.author.name}", inline=False)
            embed.add_field(name="What they tried to say:", value=f"{badword}", inline=False)
            embed.add_field(name="Channel they tried to swear in:", value=f"<#{message.channel.id}>", inline=False)
            
            return await channel.send(embed=embed)

Answer 1

如果您不关心人们试图混淆单词以通过您的系统，例如eeHOEee，您可以使用 .split(' ') 创建内容中所有单词的列表。然后您可以检查列表以查看是否找到了“坏词”。

message_content_list = (message.content.lower()).split(' ')
for badword in file:
    if badword in message_content_list:

刚刚意识到，但是由于您要迭代许多不同的单词，因此可以稍微优化一下代码：

message_content_set = set((message.content.lower()).split(' '))
for badword in file:
        if badword in message_content_set:

这应该会稍微加快这个过程，因为检查一个项目是否是 in 一个集合比检查一个列表要快。

注意：运行时的差异非常小，通常你不会这样做，除非有大量的“坏词”需要迭代。

反脏话系统黑名单非脏话

1 个答案: