如何从嵌套在列表中的每个字典中提取每个值? 目前我坚持接受一个键的列表理解。
d = [e["key1"] for e in list]
样品
[{'key1': 'value1', 'key2': 'value2'}, {'key3': 'value4', 'key4': 'value4'}]
需要获取
value1, value2, value3, value4
答案 0 :(得分:1)
>>> vals = []
>>> for d in d_list:
vals += list(d.values())
>>> vals
['value1', 'value2', 'value4', 'value4']
答案 1 :(得分:1)
通过 itertools 链 -
l = [{'key1': 'value1', 'key2': 'value2'}, {'key3': 'value4', 'key4': 'value4'}]
from itertools import chain
result = list(chain(*(item.values() for item in l)))
通过列表理解 -
result = [val for i in l for val in i.values()]
答案 2 :(得分:0)
感谢所有人和@kaya3!
[x for d in list_of_dicts for x in d.values()]