Question

我希望我的机器人加入播放命令，这样我就不必输入 !join 和 !play 来播放音乐，而只需输入 !play。我还想添加一个队列系统，让我在队列中添加歌曲并在歌曲结束时自动播放它们，使用相同的命令（播放），但我不知道如何去做。你能帮帮我吗？？？

youtube_dl.utils.bug_reports_message = lambda: ''


ytdl_format_options = {
    'format': 'bestaudio/best',
    'outtmpl': '%(extractor)s-%(id)s-%(title)s.%(ext)s',
    'restrictfilenames': True,
    'noplaylist': True,
    'nocheckcertificate': True,
    'ignoreerrors': False,
    'logtostderr': False,
    'quiet': True,
    'no_warnings': True,
    'default_search': 'auto',
    'source_address': '0.0.0.0' # bind to ipv4 since ipv6 addresses cause issues sometimes
}

ffmpeg_options = {
    'options': '-vn'
}

ytdl = youtube_dl.YoutubeDL(ytdl_format_options)


class YTDLSource(discord.PCMVolumeTransformer):
    def __init__(self, source, *, data, volume=0.5):
        super().__init__(source, volume)

        self.data = data

        self.title = data.get('title')
        self.url = data.get('url')

    @classmethod
    async def from_url(cls, url, *, loop=None, stream=False):
        loop = loop or asyncio.get_event_loop()
        data = await loop.run_in_executor(None, lambda: ytdl.extract_info(url, download=not stream))

        if 'entries' in data:
            # take first item from a playlist
            data = data['entries'][0]

        filename = data['url'] if stream else ytdl.prepare_filename(data)
        return cls(discord.FFmpegPCMAudio(filename, **ffmpeg_options), data=data)

@bot.command()
async def join (ctx):
    if not ctx.message.author.voice:
        await ctx.send("You are not connected to a voice channel")
        return
    else:
        channel=ctx.message.author.voice.channel
    await channel.connect()


@bot.command(help="This command plays a song.")
async def play (ctx,*args):
    server = ctx.message.guild
    voice_channel= server.voice_client
    url=""
    for word in args:
        url+=word
        url+=''

    async with ctx.typing():
        player = await YTDLSource.from_url(url,loop=bot.loop)
        voice_channel.play (player, after = lambda e: print("Player error: %s" % e)if e else None)
        
    await ctx.send(f"Now playing: {player.title}")

Answer 1

这将使机器人加入 !play 命令。

@bot.command(help="This command plays a song.")
async def play (ctx,*args):
    if not ctx.message.author.voice:
        await ctx.send("You are not connected to a voice channel")
        return
    else:
        channel=ctx.message.author.voice.channel
        await channel.connect()
        server = ctx.message.guild
        voice_channel= server.voice_client
        url=""
        for word in args:
            url+=word
            url+=''

        async with ctx.typing():
            player = await YTDLSource.from_url(url,loop=bot.loop)
            voice_channel.play (player, after = lambda e: print("Player error: %s" % e)if e else None)
            
        await ctx.send(f"Now playing: {player.title}")

如何在播放命令上组合队列和加入？ - 不和谐.py

1 个答案: