Question

我有一个看起来像这样的文件（带有换行符和奇怪的间距）：

Player:         Alive: Score: Ping: Member of Team: 
player1         No     16     69    dogs      
bug             Yes    2      63    insects            
name with space No     0      69    cats        
bob             No     0      69    dogs

如何抓住第一列并将其转换为数组？

期望输出：
$ players [1] ----＆gt; “player1”
$ players [2] ----＆gt; “错误”
$ players [3] ----＆gt; “空间名称”
$ players [4] ----＆gt; “鲍勃”

Answer 1

<?php
    $a=file('file.txt');
    $pos=strpos($a[0],'Alive:');
    $res=array_map(function($x) use ($pos){
        return trim(substr($x,0,$pos));
    },$a);
    unset($res[0]);

对于PHP 5.2 -

<?php
    $a=file('file.txt');
    $pos=strpos($a[0],'Alive:');
    function funcname($x,$pos){
        return trim(substr($x,0,$pos));
    }
    $res=array_map('funcname',$a,array_fill(0,count($a),$pos));
    unset($res[0]);

Answer 2

使用正则表达式的另一个选项可能如下：

preg_match_all('/^.{0,15}?(?= {2}|(?<=^.{15}))/m', $subject, $matches);
$players = $matches[0];
unset($players[0]); // remove header

var_export($players);

生成的$players数组看起来像

array (
  1 => 'player1',
  2 => 'bug',
  3 => 'name with space',
  4 => 'bob',
)

注意：与任何基于正则表达式的解决方案一样，如果上面看起来像魔术，那么请不要使用它。如果您不知道它实际上要匹配的内容，那么将正则表达式复制并粘贴到代码中绝对没有意义。

Answer 3

这是迭代器的一种方法：

class SubstringIterator extends IteratorIterator
{
    protected $startAtOffset, $endAtOffset;

    public function __construct($iterator, $startAtOffset, $endAtOffset = null) {
        parent::__construct($iterator);
        $this->startAtOffset = $startAtOffset;
        $this->endAtOffset = $endAtOffset;
    }

    public function current() {
        return substr(parent::current(), $this->startAtOffset, $this->endAtOffset);
    }
}

您可以这样使用它：

$playerIterator = new LimitIterator(
    new SubstringIterator(
        new SplFileObject('yourFile.txt'), 
        0, // start at beginning of line 
        15 // end before Alive:
    ) 
    , 1 // start at line 2 in file (omits the headline)
);

然后你可以通过迭代器foreach，例如

foreach ($playerIterator as $player) {
    echo $player, PHP_EOL;
}

输出：

player1        
bug            
name with space
bob

或者将堆叠的迭代器转换为数组：

$array = iterator_to_array($playerIterator);
print_r($array);

输出：

Array
(
    [1] => player1        
    [2] => bug            
    [3] => name with space
    [4] => bob            
)

Demo of above examples with your file's data

Answer 4

最简单的方法：

$file = file_get_contents($filepath);
$column_width = strpos($file,'Alive:') + 1;
preg_match_all('/^(.{'.$column_width.'}).*$/m', $file, $matches);
unset($matches[1][0]);
$result = array_map('trim', $matches[1]);

最终的$结果是：

array (
    0 => 'player1',
    1 => 'bug',
    2 => 'name with space',
    3 => 'bob',
  ),

PHP从行中获取第一个单词

4 个答案: