Question

我尝试了很多变化而没有运气。我可以NSLog数组，我得到了这个：

2011-07-17 00:54:54.886 Widgets[13444:207] <Widget: 0x5e2aad0> (entity: Widget; id: 0x5e0d8e0 <x-coredata://E64A0BCE-2344-4EE1-89CC-164ACD8995D6/Recipe/p115> ; data: {
    success = 1;
    coconutscarried = nil;
    name = "African Swallow";
    uidnumber = "105 ";
})

如何简单设置文本字段？

原谅这个烂摊子，但这是我尝试过的各种代码（凌乱）。数组和文本字段已设置为.h / m并绑定在IB

中

- (void)viewDidLoad {
    [super viewDidLoad];
    //NSLog(@"%@",[[swallowArray name] text]); // doesnt work
    //NSLog(@"The string at index is %@.", [self.swallowArray objectAtIndex:0]);//nope...
    for (int i = 0; i < [swallowArray count]; i++) {
        //nameTextField.text = [[swallowArray objectAtIndex:i] uidnumber];
        //NSLog(@"%@",swallowArray.name);
    //}
    //nameTextField.text = [[swallowArray objectAtIndex:0] uidnumber];
    //NSString* strRate = [[swallowArray object] uidnumber];
    nameTextField.text = [nameTextField.text stringByAppendingString:[NSString localizedStringWithFormat:@", %@", [[swallowArray objectAtIndex:i] name]]];

}

还有更多。这一定很简单，但我有点像菜鸟。

谢谢！

博

Answer 1

经过5个小时的搜索，我在这里发帖，并在五分钟内找到答案！

NSString *nameFromArray = [NSString stringWithFormat:@"%@", [eventArray valueForKey:@"name"]];
NSLog(@"%@", nameFromArray);

希望这有助于其他人！

从NSArray设置UITextField

1 个答案: