需要JavaScript / Regex来挑选和处理URL

Question

我有一个看起来像这样的字符串：

＆＃34; blah blah blah yada yada http://www.example.com/check?x=rabP4F3Mk&dept=check等等等等......＆＃34;

例如类似于上面的字符串，我需要Regex / JavaScript 代码，它返回如下字符串：＆＃34; rabP4F3Mk＆amp; dept = check＆＃34;

我将尝试更精确：

if (the string contains "example.com/check?x="){ 
   return the portion of the token that contains "example.com/check?x=" after the "="
}

Answer 1

"example.com/check?x=asdfasdf".match(/check\?x=(.*)/)[1]

Answer 2

matches = str.match(/example.com\/check\?x\=([^\s]*)/);
if(matches.length > 1) return matches[1];

Answer 3

/example\.com\/check\?x=([^\s]+)/