Question

如何过滤phrase使用php？谁能给我一个函数调用？

例如，如果我想从句子There are no user contributed notes for this page.

过滤短语'no''this'

这样句子就像There are user contributed notes for page.谢谢。

<?php
function filterBadWords($str)
{
    $badwords = array('no','this');
    $replacements = " ";
    foreach ($badwords AS $badword)
    {
          $str = eregi_replace($badword, str_repeat(' ', strlen($badword)), $str);
    }  
    return $str;
} 

$string = "There are user contributed notes for page.";
print filterBadWords($string); // this will filter `no` from `notes`
?>

Answer 1

$text = preg_replace('/\b(?:no|this)\b ?/i', '', $text);

编辑：

现在它会删除一个空格，如果它在单词后面找到一个空格，那么你最终不会在一行中有两个空格。

$text = 'There are no user contributed notes for this page.';
$text = preg_replace('/\b(?:no|this)\b ?/i', '', $text);
echo $text;

输出：页面有用户提供的注释。

<强>更新

如果您想使用数组来更轻松地管理过滤后的单词，您可以这样做：

function filterWords($string){
    $bad_words = array('no', 'this');
    return preg_replace('/\b(?:'.implode('|', $bad_words).')\b ?/i', '', $string);
}

echo filterWords('There are no user contributed notes for this page.');

Answer 2

使用str_replace

str_replace(array('no', 'this'), '', $text);

php过滤短语

2 个答案: