Question

以下给出了与匿名函数相关的语法错误：

my_function = (f, x, str) ->
  alert str + f(x)

my_function (x) -> 1 + x, 12, "The answer is: "

以下作品：

my_function = (f, x, str) ->
  alert str + f(x)

increment = (x) -> x + 1

my_function increment, 12, "The answer is: "

Answer 1

my_function ((x) -> x + 1), 12, "The answer is: "

那应该解决它。