我在我的DB 3 col中,我想在所有这些中找到一个值作为解释:table name:MyTable
-----------------------------
--id-- col1-- col2-- col3-
-----------------------------
1 200 300 400
2 100 150 300
3 800 102 20
4 80 80 0
我希望col1 col2 col3的结果为= 0,这是它们中的最小值。 有可能!!!!
我的尝试:
select Min(col1, col2 , col3) as Tablemin
from MyTable
答案 0 :(得分:6)
ANSI SQL:
select min(col)
from
(
select col1 [col] from MyTable
union all
select col2 from MyTable
union all
select col3 from MyTable
)t
答案 1 :(得分:2)
如果是MySQL或Oracle,则有LEAST()
函数:
SELECT LEAST(MIN(col1), MIN(col2), MIN(col3))
AS MinOfAllColumns
FROM MyTable
然后,有CASE
语句可以在大多数RDBMS中使用:
SELECT CASE WHEN MIN(col1) <= MIN(col2) AND MIN(col1) <= MIN(col3)
THEN MIN(col1)
WHEN MIN(col2) <= MIN(col3)
THEN MIN(col2)
ELSE MIN(col3)
END
AS MinOfAllColumns
FROM MyTable
这也可以,但很难通过UNION
方法获得其他字段:
SELECT MIN(col) AS MinOfAllColumns
FROM
( SELECT MIN(col1) AS col
FROM MyTable
UNION
SELECT MIN(col2)
FROM MyTable
UNION
SELECT MIN(col3)
FROM MyTable
) AS tmp
答案 2 :(得分:2)
显示min的简单方法是:
string val = textBox2.Text;
DataSet ds;
con.Open();
string str = "SELECT * FROM Add_Rooms WHERE Price >= @price";
cmd = new SqlCommand(str, con);
cmd.Parameters.AddWithValue("@price", val);
SqlDataAdapter da = new SqlDataAdapter(cmd);
ds = new DataSet();
da.Fill(ds, "Add_Rooms");
dataGridView1.DataSource = ds;
dataGridView1.DataMember = "Add_Rooms";
con.Close();
答案 3 :(得分:1)
在SQLITE中,答案很简单:
SELECT MIN(MIN(col1), MIN(col2), MIN(col3)) FROM MyTable;