如何修复此代码
我想检查密钥是否像列表中的密钥一样
我也想要
如果key为true用户可以使用该工具如果key为false用户不能使用该工具
keys
{
"link": "www.xxxxxxxxxxx.com",
"key": '34243242354354'
},
{
"link": "www.xxxxxxxxxxx.com",
"key": '432432534534534'
},
{
"link": "www.xxxxxxxxxxx.com",
"key": '42345534534'
}
]
number = 0
key = input("put the code to use this tool :")
for x in keys:
number = number + 1
if keys[number]["key"] == key:
print("true")
else:
print("false")
答案 0 :(得分:0)
嗨,您应该尝试使用 enumerate() 进行索引循环。
def key_func():
key = input("put the code to use this tool :")
for i ,m in enumerate(keys):
if m['key'] == key:
return True
return False
答案 1 :(得分:0)
我看到这里有 3 个问题:
你可以这样做:
number = 0
key = input("put the code to use this tool :")
for x in keys:
if keys[number]["key"] == key:
print("true")
break
elif number == (len(keys) - 1):
print("false")
number = number + 1
或者更好地使用枚举:
number = 0
key = input("put the code to use this tool :")
for number, x in enumerate(keys):
if keys[number]["key"] == key:
print("true")
break
elif number == (len(keys) - 1):
print("false")