Question

如何比较批处理文件中的两个文件，并根据它们是否匹配执行操作？我尝试过类似的东西：

if file1.txt NEQ file2.txt goto label

但它比较实际的字符串“file1.txt”而不是文件。我已经阅读了关于COMP命令的内容，但如果我把它放在if语句中它似乎不起作用。有人知道怎么做这个吗？抱歉，我很少使用批处理文件，对它们的经验很少。

提前致谢。

Answer 1

我相信您可以使用“FC”命令然后检查错误级别。这是一些代码：

@echo off
:main
fc c:\filename r:\filemame > nul
if errorlevel 1 goto error

:next
echo insert next CD
pause
goto main

:error
echo failed check

（从http://www.computing.net/answers/dos/batch-file-command/15753.html拉出来）

Answer 2

似乎COMP程序实际上相当容易使用。请参阅有关雅虎答案的this question。

请注意，运行comp /?将打印程序的帮助文本（与使用任何本机Windows命令行程序指定/?参数一样）。这将输出您在上面链接的问题的答案中看到的相同文本。

来自雅虎的内容答案：

C:\>comp /? 
Compares the contents of two files or sets of files. 

COMP [data1] [data2] [/D] [/A] [/L] [/N=number] [/C] [/OFF[LINE]] 

data1 Specifies location and name(s) of first file(s) to compare. 
data2 Specifies location and name(s) of second files to compare. 
/D Displays differences in decimal format. 
/A Displays differences in ASCII characters. 
/L Displays line numbers for differences. 
/N=number Compares only the first specified number of lines in each file. 
/C Disregards case of ASCII letters when comparing files. 
/OFF[LINE] Do not skip files with offline attribute set. 

To compare sets of files, use wildcards in data1 and data2 parameters.

Answer 3

我使用以下示例根据文件差异构建报告：

set %Batch_Work_Space_Dir%=folder for your batch file and temp resource files
set file_1=name of file
set file_2=name of file

fc %file_1% %file_1%t > %Batch_Work_Space_Dir%\Are_They_Different.txt

powershell -command "(Get-Content %Batch_Work_Space_Dir%\Are_They_Different.txt) | select -skip 1 | Set-Content %Batch_Work_Space_Dir%\Are_They_Different.txt"
set /p Diff_Found=<%Batch_Work_Space_Dir%\Are_They_Different.txt
if %Diff_Found:~0,17%" == "FC: no difference" (
  execute commands
 )

如何比较批处理文件中的两个文件？

3 个答案: