我使用symfony 1.4.11和doctrine。架构的一部分:
Companies:
actAs:
Timestampable: ~
Sluggable:
unique: true
fields: [company]
canUpdate: false
builder: [myTools, StripText]
connection: doctrine
tableName: companies
columns:
company_id: { type: integer(4), primary: true, notnull: true, autoincrement: true }
user_id: { type: int(4) }
category_id: { type: int(4), notnull: true }
company: { type: string(255), notnull: true }
address: { type: string(255), notnull: true }
contact_person: { type: string(255), notnull: true }
phone: { type: string(50), notnull: true }
fax: { type: string(50) }
email: { type: string(255), notnull: true}
url: { type: string(50) }
about: { type: string(1000), notnull: true}
country: { type: string(255), notnull: true}
show_ads: { type: boolean, default: 0 }
active: { type: boolean, default: 0 }
has_company: { type: boolean, default: 1 }
relations:
Owner: { onDelete: CASCADE, local: user_id, foreign: id, class: sfGuardUser, foreignAlias: Companies }
Images_companies: { local: company_id, foreign: company_id, type: many, class: Images_companies }
Categories: { onDelete: CASCADE, local: category_id, foreign: category_id , type: many, foreignType: one}
Categories:
actAs:
I18n:
fields: [name]
actAs:
Sluggable:
unique: true
fields: [name]
canUpdate: true
builder: [myTools, StripText]
NestedSet:
hasManyRoots: true
connection: doctrine
tableName: categories
columns:
category_id: { type: integer(4), primary: true, autoincrement: true }
name: string(255)
我希望用户可以选择公司,多个类别。我使用sfWidgetFormDoctrineChoice,所以当我有
时$this->widgetSchema['category_id'] = new sfWidgetFormDoctrineChoice(array('model' => 'Categories', 'add_empty' => false, 'multiple' => false));
用户只能选择一个类别,一切正常。 当我有:
$this->widgetSchema['category_id'] = new sfWidgetFormDoctrineChoice(array('model' => 'Categories', 'add_empty' => false, 'multiple' => true));
在db save category_id = 0中,从列表中只选择一个类别。当我选择多个类别时,我有错误: SQLSTATE [HY093]:参数号无效:绑定变量数与令牌数不匹配
我在google中搜索此错误,但我找不到决定,而且我现在不会在哪里犯错。谢谢!
答案 0 :(得分:1)
您定义关系的方式不允许您为您的公司选择多个类别。您可能希望设置多对多关系。 http://www.doctrine-project.org/projects/orm/1.2/docs/manual/defining-models/en#relationships:join-table-associations:many-to-many
答案 1 :(得分:1)
就我而言,我必须修改验证器:
$this->validatorSchema[idapplication] = new sfValidatorDoctrineChoice(
array(
model=>'hotteApplication', 'multiple' => true
)
);