我之前在上一篇文章中问过这个问题。我明白有些事情并没有我想象的那么清楚。因此,我创建了一个 100% 功能性复制代码,它应该可以说明为什么 Function{}
中的数据不能被更改(如上一篇文章中所建议的那样)。
复制代码(只需复制、粘贴和执行,您就会得到三个图形):
df <- data.frame(
ID = c(1L,1L,
1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,
1L,1L,1L,1L,1L,1L,1L,1L,2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,2L,3L,3L,3L,
3L,3L,3L,3L,3L,3L,3L),
x = as.integer(c(14400L,
13400L,12600L,11600L,10500L,9520L,8540L,
7710L,6580L,4540L,3710L,2880L,1440L,
0L,-10000L,-20900L,-31800L,-42700L,
-53600L,-64500L,-75400L,165000L,74300L,62800L,52600L,35000L,
22200L,6090L,0L,-10000L,-16500L,-23000L,-29500L,-36000L,
-42500L,-49000L,97900L,
51100L,22900L,4410L,0L,-5000L,
-7280L,-9560L,-11840L,
-14120L)),
U.x. = c(1,
0.923076923,0.846153846,0.769230769,
0.692307692,0.615,0.538,0.462,0.385,0.308,0.231,
0.154,0.077,0,-2.723,-3.134,-9.393,
-34.664,-58.576,-188.332,-307.888,1,0.857,0.714,0.571,0.429,0.286,0.143,
0,-0.091,-0.238,-0.265,-0.447,-0.472,-0.507,-0.574,1,0.75,
0.5,0.25,0,-0.142,-0.193,
-0.322,-0.56,-0.755))
ID = c(0) #Needs to be set before starting the function, otherwise the first plot wont be generated
plot_utility <- function(ID) {
x = df$x[df$ID==ID]
y = df$U.x.[df$ID==ID]
z = df$ID[df$ID==ID]
df1 = data.frame(df$ID[df$ID==ID], df$U.x.[df$ID==ID],
df$x[df$ID==ID])
# Set boundaries and stepsize for x-axis
lowboundx <- df[df$ID==ID,][nrow(df[df$ID==ID,]), 2]
upboundx <- df[df$ID==ID,][1, 2]
# Determine sequence for x-axis with respectively lower bound (seq1) and upper bound (seq2)
seq1x <- floor(lowboundx / 5000) * 5000
seq2x <- ceiling(upboundx / 5000) * 5000
# Set boundaries and stepsize for y-axis
lowboundy <- df[df$ID==ID,][nrow(df[df$ID==ID,]), 3]
upboundy <- df[df$ID==ID,][1, 3]
# Determine sequence for x-axis with respectively lower bound (seq1) and upper bound (seq2)
if(lowboundy <= -55) {
seq1y <- floor(lowboundy / 50) * 50
seq2y <- upboundy # This is always 1
} else {
seq1y <- round(lowboundy, digits = 3)#ceiling(lowboundy / 50) * 50
seq2y <- upboundy # This is always 1
}
ggplot(df1, aes(x = x, y = y)) +
geom_point(shape=15) +
geom_hline(yintercept = 0, linetype="dashed", color = "red") +
geom_vline(xintercept = 0, linetype="dashed", color = "red") +
scale_x_continuous(name="Euro", limits = c(seq1x, seq2x), labels = comma) +
scale_y_continuous(name="U(x)", limits = c(seq1y, seq2y)) +
labs(title = paste("Subject", ID))
}
repeat {
ID = ID + 1
print(plot_utility(ID))
print(ID)
if (ID == 3){
break
}
}
我的问题是什么:
如主题 1 所示:
在图表的右侧,x 轴以 0 结尾,但在此 0 之后仍有点。x 轴需要扩展到 20,000
如主题 2 所示
这是一个比其他例子更难的例子,但原理是一样的。在 x 轴上的标签外有一个点。需要有一个额外的标签,上面写着 200,000。这听起来有点极端,但我更喜欢当前图表
如主题 3 所示
在左下角(y 轴和 x 轴在一起的地方),轴上的标签外有一些点(-0.5 和 0),我需要将其解析为额外标签(-1.0 和 - 25,000)这将是一个额外的断点(我想这就是所谓的) y 轴应该看起来像这样(从下到上): -1.0, -0.5, 0.0, 0.5, 1.0 x 轴应如下所示(从左到右): -25,000 | 0 | 25,000 | 50,000 | 75,000 | 100,000
值得注意的是,无法通过 limits =
处的 scale_x_continuous
更改此设置,因为这也会使所有其他图形发生变异,而这并不是真正需要的。
我的问题的任何解决方案将不胜感激! :) (请注意:data.frame 被逆向工程以创建此示例,请不要注意代码中不必要的值命名:))
答案 0 :(得分:0)
这是一个使用 facet_grid()
进行分面的案例。如果您需要单独的图,那么这不是适合您的解决方案。当您对情节进行分面时,您可以设置 scales = "free"
来完成您想要的结局。另请注意,此方法不需要如此复杂的代码。
ggplot(df, aes(x = x, y = U.x.)) +
geom_point(shape=15) +
geom_hline(yintercept = 0, linetype="dashed", color = "red") +
geom_vline(xintercept = 0, linetype="dashed", color = "red") +
scale_x_continuous(name="Euro") +
scale_y_continuous(name="U(x)") +
facet_grid(rows = vars(ID), scales = "free", labeller = label_both)