在为webservice开发适配器时,我最终面临这样的响应:
<?xml version="1.0" encoding="UTF-8"?>
<ResponseHeader version="1.0">
<ResponseCode>T100</ResponseCode>
<SubmissionIdentifier>1</SubmissionIdentifier>
</ResponseHeader>
<?xml version="1.0" encoding="UTF-8"?>
<SubmissionProgress xmlns="sss"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
status="inProgress"
submissionIdentifier="1"
submissionType="live">
<PFile status="rejected"
index="1"
pFileIdentifier="999">
<Exception errorCode="2001" outcomeType="rejectFile">
<Description>There.file. </Description>
<SourceRecord index="3">...</SourceRecord>
</Exception>
</PFile>
</SubmissionProgress>
xjc已成功生成 ResponseHeader 和 SubmissionProgress (以及其中的每个元素)类,如果我将此字符串拆分为2个不同的字符串,我可以完全解组这两个类。
但是,如果我把它保存在同一个字符串中并尝试将它传递给两个unmarshallers顺序它会在第一个unmarshall中断。
我正在使用此代码从一个字符串解组:
Reader reader = new StringReader(response);
JAXBContext jcrh = JAXBContext.newInstance(ResponseHeader.class);
JAXBContext jcsp = JAXBContext.newInstance(SubmissionProgress.class);
Unmarshaller urh = jcrh.createUnmarshaller();
Unmarshaller usp = jcsp.createUnmarshaller();
ResponseHeader rh = (ResponseHeader) urh.unmarshal(reader);
SubmissionProgress sr = (SubmissionProgress) usp.unmarshal(reader);
我得到以下异常(在 ResponseHeader rh =(ResponseHeader)urh.unmarshal(reader); ):
uk.co.bacs.submissions.ResponseHeader@fced4
javax.xml.bind.UnmarshalException
- with linked exception:
[org.xml.sax.SAXParseException: The processing instruction target matching "[xX][mM][lL]" is not allowed.]
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.createUnmarshalException(AbstractUnmarshallerImpl.java:315)
(...)
在这些情况下是否有一些JAXB调整(一个流中有多个XML文件)?
答案 0 :(得分:2)
我不知道JAXB的调整;我做这种事情的方式是实现一个XmlEventReader(或XmlStreamReader),它在需要时模拟文档结束。请注意,Unmarshaller.unmarshal()将其中一个作为参数。要确保正确显示事件序列,请观看“正常”文档的事件序列。你会做两个unmarshal()s。
答案 1 :(得分:0)
由于JAXB无法单独读取文件,因此我找到了两种可行的解决方案。
第一个也是更简单的一个,如果流很小,将把它全部读成一个字符串并将其拆分
String xml = "<?xml ... <?xml ...";
String[] xmlArray = xml.split("<\\?xml");
ObjectA a = (ResponseHeader) u.unmarshal(new StringReader("<?xml"+xmlArray[1]);
ObjectB b = (SubmissionProgress) u2.unmarshal(new StringReader("<?xml"+xmlArray[2));
但是,作为练习,为了更清晰的代码以及将来使用更大的流(一次处理一个对象),我制作了MultiXMLDocReader类
import java.io.BufferedReader;
import java.io.IOException;
import java.io.Reader;
public class MultiXMLDocReader extends Reader {
private BufferedReader reader;
private String buffer;
private int bufferPos;
private boolean firstDocument;
private boolean realEOF;
private boolean enforceEOF;
public MultiXMLDocReader(Reader reader) {
this.reader = new BufferedReader(reader);
firstDocument = true;
buffer = "";
bufferPos = 0;
realEOF = enforceEOF = false;
}
@Override
public void close() throws IOException {
enforceEOF = false;
if (realEOF) reader.close();
}
@Override
public int read() throws IOException {
char[] buffer = new char[1];
int result = read(buffer, 0, 1);
if (result < 0) return -1;
return buffer[0];
}
@Override
public int read(char[] cbuf, int off, int len) throws IOException {
if (enforceEOF) return -1;
int lenLeft = len;
int read = 0;
while (lenLeft > 0) {
if (buffer.length()>0) {
char[] lbuffer = buffer.toCharArray();
int bufLen = buffer.length() - bufferPos;
int newBufferPos = 0;
if (lenLeft < bufLen) {
bufLen = lenLeft;
newBufferPos = bufferPos + bufLen;
}
else buffer = "";
System.arraycopy(lbuffer, bufferPos, cbuf, off, bufLen);
read += bufLen;
lenLeft -= bufLen;
off += bufLen;
bufferPos = newBufferPos;
continue;
}
buffer = reader.readLine();
if (buffer == null) {
realEOF = true;
enforceEOF = true;
return (read == 0 ? -1 : read);
}
else
buffer += "\n";
if (buffer.startsWith("<?xml")) {
if (firstDocument) firstDocument = false;
else {
enforceEOF = true;
return (read == 0 ? -1 : read);
}
}
}
return read;
}
}
可以像
一样轻松使用MultiXMLDocReader xmlReader = new MultiXMLDocReader(new InputStreamReader(anyInputStream));
ObjectA a = (ResponseHeader) u.unmarshal(xmlReader);
ObjectB b = (SubmissionProgress) u2.unmarshal(xmlReader);
不将整个流加载到字符串。