我在Android中有一项活动,以背景图片的形式显示。当我点击背景时,我使用intent
进行另一项活动....
以下是我的代码的样子:
public class Precisari extends Activity{
protected boolean _active = true;
protected int _splashTime = 10000;
public SplashThread splashThread;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.precisari);
splashThread=new SplashThread();
}
public class SplashThread extends Thread
{
public SplashThread()
{
}
public void run() {
try {
int waited = 0;
while (_active && (waited < _splashTime)) {
sleep(100);
if (_active) {
waited += 100;
}
}
} catch (InterruptedException e) {
// do nothing
} finally {
//finish();
Intent i = new Intent(getBaseContext(), com.SplashScreen.ConnectWithFb.class);
startActivity(i);
stop();
}
}
}
public boolean onTouchEvent(MotionEvent event){
if(event.getAction()==MotionEvent.ACTION_DOWN){
_active=false;
}
return true;
}
public void onResume(){
super.onResume();
_active=true;
splashThread.start();
}
public void onPause()
{
super.onPause();
splashThread.stop();
}
}
我正在使用一个我在onResume()
开始的线程......这个线程循环直到布尔变量_active
设置为false。当我点击屏幕时,变量设置为false模拟器:
public boolean onTouchEvent(MotionEvent event){
if(event.getAction()==MotionEvent.ACTION_DOWN){
_active=false;
}
return true;
}
然后我使用intent传递给下一个活动:
Intent i = new Intent(getBaseContext(), com.SplashScreen.ConnectWithFb.class);
线程在onResume()
中启动并在onPause()
中停止。我的想法是,当我回到此活动时,我希望同样的想法能够工作......传递给下一个活动当我点击屏幕时!
以下是我的logcat的样子:
Uncaught handler: thread main exiting due to uncaught exception
java.lang.RuntimeException: Unable to resume activity {com.SplashScreen/com.SplashScreen.Precisari}: java.lang.IllegalThreadStateException: Thread already started.
at android.app.ActivityThread.performResumeActivity(ActivityThread.java:2950)
at android.app.ActivityThread.handleResumeActivity(ActivityThread.java:2965)
at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1889)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:123)
at android.app.ActivityThread.main(ActivityThread.java:4363)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:521)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:860)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:618)
at dalvik.system.NativeStart.main(Native Method)
Caused by: java.lang.IllegalThreadStateException: Thread already started. at java.lang.Thread.start(Thread.java:1322)
at com.SplashScreen.Precisari.onResume(Precisari.java:101)
at android.app.Instrumentation.callActivityOnResume(Instrumentation.java:1149)
at android.app.Activity.performResume(Activity.java:3763)
at android.app.ActivityThread.performResumeActivity(ActivityThread.java:2937)
可以请别人告诉我我做错了吗?
答案 0 :(得分:1)
您获得该异常的原因是因为停止并重新启动单个Thread对象实例是非法的。你分别在onResume / onPause中调用start / stop,但你永远不会重新分配线程对象(来自onCreate)。
要停止并重新启动线程,您需要重新分配Thread对象。
Android源代码在这方面相当明确:
// Thread.java, line ~178
/**
* Reflects whether this Thread has already been started. A Thread
* can only be started once (no recycling). Also, we need it to deduce
* the proper Thread status.
*/
boolean hasBeenStarted = false;
// Thread.java, line ~1043
public synchronized void start()
{
if (hasBeenStarted) {
throw new IllegalThreadStateException("Thread already started."); // TODO Externalize?
}
hasBeenStarted = true; // <--- Look here!
VMThread.create(this, stackSize);
}
即使线程退出,hasBeenStarted 也永远不会重置为false。
答案 1 :(得分:-3)
将sleep(100)置于try catch块中。