Mysql结果集中的动态下拉菜单

Question

我想从以下结果集创建一个动态菜单。

Html结构应如下，

<ul class="menu">

<li>Menu 1</li> 
  <ul class='submenu'> 
     <li>Submenu1</li> 
     <li>Submenu2</li> 
  </ul>    
<li>Menu2</li> 
  <ul class='submenu'> 
     <li>Submenu1</li> 
     <li>Submenu2</li> 
  </ul> 
<li>Menu 3</li> 
</ul>

尝试如下，

<?php $cat = 0;?> 
<?php foreach($this->submenus as $submenu): ?>

        <?php if($cat!= $submenu->category_id): ?>


                        <li><?php echo $submenu->category_name ?></li>

                        <?php echo (!empty($submenu->subcategory_name))?'<ul>':'';        ?>

                        <?php $flag = $submenu->category_id; ?>

        <?php endif;?>

                        <li class='sub'><?php echo $submenu->subcategory_name ?></li>

        <?php if($cat!= $flag && $cat > 0): ?>
                </ul>
        <?php endif;?>                                        

                <?php  $cat = $submenu->category_id;?>


<?php endforeach; ?>

关闭时失败。

请帮忙。

由于

Answer 1

您可以使用Accordion菜单执行此任务。

请参阅此链接http://chandreshmaheshwari.wordpress.com/2011/05/27/accordian-menu/

感谢。

Answer 2

我稍微重新安排了您的PHP代码，请尝试以下操作：

<?php $cat = 0;?> 
<?php $submenu_flag = 0;?> 

<?php foreach($this->submenus as $submenu): ?>

        <?php if($cat!= $submenu->category_id): ?>


                <?php if($submenu_flag > 0): ?>
                        </ul>
                <?php $submenu_flag = 0;?> 
                <?php endif;?>                                        

                        <li><?php echo $submenu->category_name ?></li>


                <?php if(!empty($submenu->subcategory_name)): ?>
                        <ul>
                            <?php $submenu_flag = 1; ?>
                <?php endif;?>                                        


        <?php endif;?>


            <?php echo (!empty($submenu->subcategory_name))?'<li class='sub'><?php echo $submenu->subcategory_name ?></li>':'';        ?>


            <?php  $cat = $submenu->category_id;?>


<?php endforeach; ?>