我最近创建了一个播放广播的不和谐机器人,我想知道如何确保在没有人的情况下机器人引导它。
if (oldState.channelID !== oldState.guild.me.voice.channelID || newState.channel)
return;
// otherwise, check how many people are in the channel now
if (!oldState.channel.members.size === 1)
setTimeout(() => { // if 1 (you), wait five minutes
if (!oldState.channel.members.size === 1) // if there's still 1 member,
oldState.channel.leave(); // leave
}, 10);
});
我测试了这个,但它不起作用,有人可以帮助我吗?谢谢!
答案 0 :(得分:0)
试试这个:
client.on('voiceStateUpdate', (oldState, newState) => {
if (oldState.channelID !== oldState.guild.me.voice.channelID || newState.channel){
return(0); //If it's not the channel the bot's playing in
}
if((oldState.channel.members.size -1) <= 1){
//The bot's still in channel so it's never be zero
//So we'll use <=1
oldState.channel.leave(); //Leave the channel
}
});
如果您想在一段时间后触发它,请输入 setTimeout
的或者:强>
client.on('voiceStateUpdate', (oldState, newState) => {
if (oldState.channelID !== oldState.guild.me.voice.channelID || newState.channel){
return(0); //If it's not the channel the bot's playing in
}
if(!oldState.channel.members.size -2){
//The bot's still in channel so it's never be zero
//We'll use -2 this time
oldState.channel.leave(); //Leave the channel
}
});
评论应该是不言自明的