我正在尝试按如下方式实现 DispatchGroup
,但如果第一个调用返回 true
,那么第二个调用返回 false
,那么总体结果将返回 false
。
但是,如果第一个调用返回 false
,然后第二个调用返回 true
,那么总体结果将返回 false
,这不是我所期望的。
如果任何调用返回 false
,我想返回 false
。我该如何处理这个问题?
func storeInformation(id: String?, _ completion: @escaping (Bool) -> ()) {
guard
let id = id
else {
completion(false)
return
}
let dispatchGroup = DispatchGroup()
var groupResult: Bool = false
dispatchGroup.enter()
storeFeatures { success in
if success {
groupResult = true
} else {
groupResult = false
}
dispatchGroup.leave()
}
dispatchGroup.enter()
storeClasses { success in
if success {
groupResult = true
} else {
groupResult = false
}
dispatchGroup.leave()
}
dispatchGroup.notify(queue: .main) {
completion(groupResult)
}
}
private func storeClasses(_ completion: @escaping(Bool) -> Void) {
postClasses { (error) in
if let _ = error {
completion(false)
} else {
completion(true)
}
}
}
private func storeFeatures(_ completion: @escaping(Bool) -> Void) {
postFeatures { (error) in
if let _ = error {
completion(false)
} else {
completion(true)
}
}
}
答案 0 :(得分:2)
如果我们查看您的 storeClasses
和 storeFeatures
,我们会发现它们不是真正返回布尔值的操作;它们本质上是尝试发布一些可能会失败的东西。因此,您真正想知道的不是返回 true
或 false
的东西,而是它是否失败。这就是你真正的意思 - 在编程中,说出你的意思总是更好。
使用Combine 框架,我们可以以难以置信的简洁方式表达这种行为。当我们有多个异步操作要同时执行时,这就是合并。如果其中一个失败,整个合并失败。换句话说,您想做的事情实际上是自动的!
想象一下,例如,我们通过将您的发布操作包装在类型为 <Void,Error>
的延迟期货中来表达您的发布操作。假设我们有方法 storeClassesFuture
和 storeFeaturesFuture
产生这些 Futures。那么你只需要说:
Publishers.Merge(storeClassesFuture(), storeFeaturesFuture())
这就是它的全部内容!如果您使用 sink
订阅该合并,则它会收到 finished
完成或 failure
完成。你猜怎么着?它接收 failure
完成 当且仅当一个或两个 post 操作失败!它仅在它们都成功时接收 finished
完成,这正是你想知道什么。
作为测试平台,以下是您的 storeInformation
的示例实现(出于示例目的,我忽略了字符串):
var storage = Set<AnyCancellable>()
enum Oops : Error { case darn }
func storeInformation() {
Publishers.Merge(storeClassesFuture(), storeFeaturesFuture())
.receive(on: DispatchQueue.main)
.sink { (completion) in
switch completion {
case .failure: print("at least one of them failed")
case .finished: print("they both succeeded")
}
print("---")
} receiveValue: { _ in }
.store(in: &storage)
}
为了作为随机测试,这里有两个可以随机成功或失败的未来:
func storeClassesFuture() -> AnyPublisher<Void,Error> {
Deferred {
Future<Void,Error> { promise in
if Bool.random() {
print("storeClassesFuture succeeded")
promise(.success(()))
} else {
print("storeClassesFuture failed")
promise(.failure(Oops.darn))
}
}
}.eraseToAnyPublisher()
}
func storeFeaturesFuture() -> AnyPublisher<Void,Error> {
Deferred {
Future<Void,Error> { promise in
if Bool.random() {
print("storeFeaturesFuture succeeded")
promise(.success(()))
} else {
print("storeFeaturesFuture failed")
promise(.failure(Oops.darn))
}
}
}.eraseToAnyPublisher()
}
这里是重复调用 storeInformation
的一些示例输出:
storeClassesFuture succeeded
storeFeaturesFuture succeeded
they both succeeded
---
storeClassesFuture failed
storeFeaturesFuture failed
at least one of them failed
---
storeClassesFuture failed
storeFeaturesFuture succeeded
at least one of them failed
---
storeClassesFuture failed
storeFeaturesFuture failed
at least one of them failed
---
storeClassesFuture failed
storeFeaturesFuture succeeded
at least one of them failed
---
storeClassesFuture succeeded
storeFeaturesFuture succeeded
they both succeeded
---
storeClassesFuture succeeded
storeFeaturesFuture succeeded
they both succeeded
---
storeClassesFuture failed
storeFeaturesFuture succeeded
at least one of them failed
---
storeClassesFuture failed
storeFeaturesFuture succeeded
at least one of them failed
---
storeClassesFuture succeeded
storeFeaturesFuture succeeded
they both succeeded
---
如您所见,两个可失败的 Future 的合并完美地表达了您所追求的逻辑。
(这种事情是采用Combine框架而不是使用DispatchGroup的一个很好的理由。我发现我以前用DispatchGroup做的一切都可以用Combine做得更好。这恰好是一个特别明确的例子。 )
答案 1 :(得分:1)
这里有一个“AND”语义,所以你应该在你的代码中写下它:
let dispatchGroup = DispatchGroup()
var groupResult: Bool = true // identity for AND
dispatchGroup.enter()
storeFeatures { success in
groupResult = groupResult && success // here!
dispatchGroup.leave()
}
dispatchGroup.enter()
storeClasses { success in
groupResult = groupResult && success // and here
dispatchGroup.leave()
}
dispatchGroup.notify(queue: .main) {
completion(groupResult)
}
当每个任务完成时,你想表达的想法
<块引用>如果前一组结果为真且成功为真,则该组结果应为真